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In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:
- a)3 and 9
- b)4 and 3
- c)3 and 1
- d)4 and 9
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In a reverted gear train the pinion (20 teeth) drives a gear B (60 tee...
Reverted Gear Train Calculation
First Stage: Pinion A (20 teeth) drives Gear B (60 teeth)
- Module: 3
- Velocity Ratio: 60/20 = 3
Second Stage: Gear B and Pinion C (15 teeth) are compounded and drives Output Gear D (45 teeth)
- Module: ?
- Velocity Ratio: 45/15 = 3
To find the module for the second stage, we can use the formula:
Module = (Pitch Diameter of Driven Gear - Pitch Diameter of Driving Gear) / Number of Teeth on the Driving Gear
Pitch Diameter of Gear B = Module x Number of Teeth on Gear B
= 3 x 60
= 180 mm
Pitch Diameter of Pinion C = Module x Number of Teeth on Pinion C
= M x 15
Since Gear B and Pinion C are compounded, their pitch circles are the same size. Therefore, we can set their pitch diameters equal to each other:
180 = M x 60/15
M = 4 mm
Therefore, the module for the second stage is 4 mm and the velocity ratio is 3. Multiplying the velocity ratios of both stages, we get a total velocity ratio of 3 x 3 = 9.
Hence, the correct answer is option D (4 and 9).
First Stage: Pinion A (20 teeth) drives Gear B (60 teeth)
- Module: 3
- Velocity Ratio: 60/20 = 3
Second Stage: Gear B and Pinion C (15 teeth) are compounded and drives Output Gear D (45 teeth)
- Module: ?
- Velocity Ratio: 45/15 = 3
To find the module for the second stage, we can use the formula:
Module = (Pitch Diameter of Driven Gear - Pitch Diameter of Driving Gear) / Number of Teeth on the Driving Gear
Pitch Diameter of Gear B = Module x Number of Teeth on Gear B
= 3 x 60
= 180 mm
Pitch Diameter of Pinion C = Module x Number of Teeth on Pinion C
= M x 15
Since Gear B and Pinion C are compounded, their pitch circles are the same size. Therefore, we can set their pitch diameters equal to each other:
180 = M x 60/15
M = 4 mm
Therefore, the module for the second stage is 4 mm and the velocity ratio is 3. Multiplying the velocity ratios of both stages, we get a total velocity ratio of 3 x 3 = 9.
Hence, the correct answer is option D (4 and 9).
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In a reverted gear train the pinion (20 teeth) drives a gear B (60 tee...
When the axes of the first gear (i.e. first driver) and the last gear (i.e. last driven) are co-axial, then the gear train is known as a reverted gear train.
TA = 20, TB = 60, TC = 15, TD = 45
Distance between the centres of the shafts:
rA + rB = rC + rD
rA + rB = rC + rD
Module, m = D (mm) / T
m (TA + TB) = m' (TC + TD)
3(20 + 60) = m' (15 + 45)
m' = (80 * 3) / 60 = 4
m (TA + TB) = m' (TC + TD)
3(20 + 60) = m' (15 + 45)
m' = (80 * 3) / 60 = 4
Velocity Ratio:
ND driven / ND driven = Product of number of teeth on driven / Product of number of teeth on drivers
ND driven / ND driven = Product of number of teeth on driven / Product of number of teeth on drivers
V. R = NA / ND = TB * TD / TA * TC
V. R = 60 * 45 / 20 * 15 = 9
V. R = 60 * 45 / 20 * 15 = 9
So, m' = 4 and V.R = 9
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In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer?.
In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer?.
Solutions for In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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ample number of questions to practice In a reverted gear train the pinion (20 teeth) drives a gear B (60 teeth). The gear B and pinion C (15 teeth) are compounded. The pinion C drives the output gear D (45 teeth). The module for the first stage is 3. The module for the second stage and the velocity ratio are respectively:a)3 and 9b)4 and 3c)3 and 1d)4 and 9Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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