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The colour of potassium dichromate is due to:
  • a)
    d–d transition
  • b)
    Transition in K+ ion.
  • c)
    Ligand to metal charge transfer
  • d)
    Metal-to-ligand charge transfer
Correct answer is option 'C'. Can you explain this answer?
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The colour of potassium dichromate is due to:a)d–d transitionb)T...
Potssium dichromate(K2Cr2O7) and potassium permangnate(KMnO4) both are coloured compounds.The purple colour KMnO4 and reddish yellow colour of K2Cr2O7 is due the charge transfer spectra.The deep purple color of the solution of KMnO4 is because-- an electron from a “oxygen lone pair” character orbital is transferred to .
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The colour of potassium dichromate is due to:a)d–d transitionb)T...
Explanation:

The colour of potassium dichromate is due to ligand to metal charge transfer.

Ligand to metal charge transfer (LMCT) is a process where a metal ion accepts an electron from a ligand, resulting in a charge transfer that leads to the formation of a complex with a different colour.

Potassium dichromate is a bright orange-red crystalline solid that is commonly used as an oxidising agent in many chemical reactions. The colour of potassium dichromate is due to the presence of Cr2O72- ions, which are the chromate ions.

In the presence of a ligand, such as water, the chromate ion undergoes LMCT, where the electron in the ligand is transferred to the metal ion. This results in the formation of a complex with a different colour.

In the case of potassium dichromate, the orange-red colour is due to the LMCT between the chromate ion and water molecules. The water molecules act as the ligands, and the Cr2O72- ion acts as the metal ion.

As the ligands vary, the colour of the complex changes. For example, the colour of the complex formed between the chromate ion and ammonia is yellow. This is because the ammonia molecules donate electrons to the metal ion, resulting in a different LMCT process and a different colour.

In conclusion, the colour of potassium dichromate is due to LMCT between the chromate ion and water molecules, resulting in the formation of an orange-red complex.
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The colour of potassium dichromate is due to:a)d–d transitionb)T...
Explanation:

Potassium dichromate (K2Cr2O7) is a bright orange-red crystalline solid that is used as an oxidizing agent in various chemical reactions. The colour of potassium dichromate is due to the phenomenon of Ligand to Metal Charge Transfer (LMCT).

What is Ligand to Metal Charge Transfer (LMCT)?

Ligand to Metal Charge Transfer (LMCT) is a type of electronic transition that occurs when an electron from a ligand is transferred to a metal ion in a coordination complex. This transfer results in the formation of a new electronic state, which is responsible for the absorption of light and the characteristic colour of the complex.

How does LMCT occur in potassium dichromate?

In potassium dichromate, the dichromate ion (Cr2O7 2-) acts as the ligand, while the potassium ion (K+) acts as the metal ion. The dichromate ion has a total of six oxygen atoms, each with a lone pair of electrons. These lone pairs can interact with the d-orbitals of the chromium ion (Cr6+) in the complex.

When light of a suitable wavelength is incident on the complex, an electron from one of the oxygen atoms is excited to a higher energy level. This excited electron then undergoes LMCT to the chromium ion, resulting in the formation of a new electronic state that is responsible for the absorption of light and the characteristic orange-red colour of potassium dichromate.

In summary, the colour of potassium dichromate is due to the phenomenon of Ligand to Metal Charge Transfer (LMCT), which occurs when an electron from one of the oxygen atoms in the dichromate ion is transferred to the chromium ion in the complex. This LMCT results in the formation of a new electronic state that is responsible for the absorption of light and the characteristic colour of the complex.
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The colour of potassium dichromate is due to:a)d–d transitionb)Transition in K+ ion.c)Ligand to metal charge transferd)Metal-to-ligand charge transferCorrect answer is option 'C'. Can you explain this answer?
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