To determine the enthalpy change when 1 mole of Ca(OH)2 is completely neutralized by CH3COOH, we need to calculate the heat of reaction using the heat of dissociation of CH3COOH.

The balanced chemical equation for the neutralization reaction is:

Ca(OH)2 + 2CH3COOH → Ca(CH3COO)2 + 2H2O

- Heat of Reaction Calculation:
The heat of reaction can be calculated using the formula:

ΔH = Σ(nΔHf(products)) - Σ(nΔHf(reactants))

where ΔH is the enthalpy change, n is the stoichiometric coefficient, and ΔHf is the heat of formation.

- ΔHf Calculation:
First, we need to calculate the moles of Ca(OH)2 and CH3COOH involved in the reaction.

From the balanced equation, we can see that 1 mole of Ca(OH)2 reacts with 2 moles of CH3COOH.

Given that the heat of dissociation of CH3COOH is 0.005 kcal g-1, we can convert it to kcal mole-1 using the molar mass of CH3COOH (60.05 g/mol).

Heat of dissociation of CH3COOH = 0.005 kcal g-1
Molar mass of CH3COOH = 60.05 g/mol

Heat of dissociation of CH3COOH = 0.005 kcal g-1 * (1 mol / 60.05 g) = 0.0000832 kcal mol-1

Now, we can calculate the enthalpy change using the formula:

ΔH = Σ(nΔHf(products)) - Σ(nΔHf(reactants))

- ΔHf(reactants):
ΔHf(Ca(OH)2) = 0 kcal/mol (as it is in its standard state)
ΔHf(CH3COOH) = 0.0000832 kcal/mol (calculated above)

- ΔHf(products):
ΔHf(Ca(CH3COO)2) = 0 kcal/mol (as it is in its standard state)
ΔHf(H2O) = 0 kcal/mol (as it is in its standard state)

Substituting the values into the equation:

ΔH = (1 * 0 kcal/mol + 2 * 0.0000832 kcal/mol) - (0 + 0)

ΔH = 0.0001664 kcal/mol

As the enthalpy change is typically expressed per mole of reaction, we can multiply it by the number of moles of reaction.

In this case, 1 mole of Ca(OH)2 is completely neutralized by CH3COOH.

ΔH = 0.0001664 kcal/mol * 1 mol = 0.0001664 kcal

Converting the units to kcal:

ΔH = 0.0001664 kcal = 0.1664 kcal

Rounding to the appropriate number of significant figures, the enthalpy change is approximately 0.1664 kcal.

However, the given options are in negative values. Since the reaction is exothermic, we need to consider the negative sign.

Therefore, the correct answer is