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In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.
Correct answer is '622222'. Can you explain this answer?
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In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A i...
Explanation:
The AT/GC ratio in E.coli DNA is 0.90. This means that for every 9 base pairs, there are 4 adenine (A) and 5 thymine (T) pairs, and 3 cytosine (C) and 2 guanine (G) pairs.
Step 1: Calculate the number of moles of T in the DNA sample.
We know that the number of moles of A is 560,000. Since A pairs with T in DNA, the number of moles of T will be the same.
Number of moles of T = 560,000
Step 2: Calculate the total number of moles of AT pairs in the DNA sample.
Since the AT/GC ratio is 0.90, for every 9 base pairs, there are 4 A-T pairs.
Number of A-T pairs = (4/9) x total number of base pairs
Since we do not know the total number of base pairs, let us assume it to be 1,000,000 for ease of calculation.
Number of A-T pairs = (4/9) x 1,000,000 = 444,444
The total number of moles of A-T pairs will be twice the number of moles of A or T.
Number of moles of A-T pairs = 2 x 560,000 = 1,120,000
Step 3: Calculate the total number of moles of GC pairs in the DNA sample.
Since the AT/GC ratio is 0.90, for every 9 base pairs, there are 3 G-C pairs.
Number of G-C pairs = (3/9) x total number of base pairs
Number of G-C pairs = (3/9) x 1,000,000 = 333,333
The total number of moles of G-C pairs will be twice the number of moles of G or C.
Number of moles of G-C pairs = 2 x number of moles of C + 2 x number of moles of G
Since we do not know the number of moles of C or G, let us assume that the number of moles of C is x.
Number of moles of G-C pairs = 2x + 2 x number of moles of G
We can rewrite this as:
Number of moles of G-C pairs = 2(x + number of moles of G)
We know that the total number of moles of A-T pairs and G-C pairs is 1,120,000.
Number of moles of G-C pairs + Number of moles of A-T pairs = 1,120,000
Substituting the value of number of moles of G-C pairs, we get:
2(x + number of moles of G) + 1,120,000 = 1,120,000
Simplifying this equation, we get:
x + number of moles of G = 0
This means that the number of moles of C is equal to the number of moles of G.
Step 4: Calculate the number of moles of G in the DNA sample.
Since the number of moles of C is equal to the number of
The AT/GC ratio in E.coli DNA is 0.90. This means that for every 9 base pairs, there are 4 adenine (A) and 5 thymine (T) pairs, and 3 cytosine (C) and 2 guanine (G) pairs.
Step 1: Calculate the number of moles of T in the DNA sample.
We know that the number of moles of A is 560,000. Since A pairs with T in DNA, the number of moles of T will be the same.
Number of moles of T = 560,000
Step 2: Calculate the total number of moles of AT pairs in the DNA sample.
Since the AT/GC ratio is 0.90, for every 9 base pairs, there are 4 A-T pairs.
Number of A-T pairs = (4/9) x total number of base pairs
Since we do not know the total number of base pairs, let us assume it to be 1,000,000 for ease of calculation.
Number of A-T pairs = (4/9) x 1,000,000 = 444,444
The total number of moles of A-T pairs will be twice the number of moles of A or T.
Number of moles of A-T pairs = 2 x 560,000 = 1,120,000
Step 3: Calculate the total number of moles of GC pairs in the DNA sample.
Since the AT/GC ratio is 0.90, for every 9 base pairs, there are 3 G-C pairs.
Number of G-C pairs = (3/9) x total number of base pairs
Number of G-C pairs = (3/9) x 1,000,000 = 333,333
The total number of moles of G-C pairs will be twice the number of moles of G or C.
Number of moles of G-C pairs = 2 x number of moles of C + 2 x number of moles of G
Since we do not know the number of moles of C or G, let us assume that the number of moles of C is x.
Number of moles of G-C pairs = 2x + 2 x number of moles of G
We can rewrite this as:
Number of moles of G-C pairs = 2(x + number of moles of G)
We know that the total number of moles of A-T pairs and G-C pairs is 1,120,000.
Number of moles of G-C pairs + Number of moles of A-T pairs = 1,120,000
Substituting the value of number of moles of G-C pairs, we get:
2(x + number of moles of G) + 1,120,000 = 1,120,000
Simplifying this equation, we get:
x + number of moles of G = 0
This means that the number of moles of C is equal to the number of moles of G.
Step 4: Calculate the number of moles of G in the DNA sample.
Since the number of moles of C is equal to the number of
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In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.Correct answer is '622222'. Can you explain this answer?
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In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.Correct answer is '622222'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.Correct answer is '622222'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.Correct answer is '622222'. Can you explain this answer?.
In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.Correct answer is '622222'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.Correct answer is '622222'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In E. coli DNA, the AT/GC ratio is 0.90. If the number of moles of A in the DNA sample is 560,000, calculate the number of moles of guanine present.Correct answer is '622222'. Can you explain this answer?.
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