Find the degree of hardness of a Sample of water containing 12mg of MgSo4 per kg of water. Please answer fast.?

Question

Answer

Degree of Hardness of Water Containing MgSo4

Hardness of water is defined as the measure of the amount of calcium and magnesium ions present in the water. The higher the concentration of these ions in water, the harder the water becomes. The hardness of water is measured in terms of mg/L or ppm (parts per million).

Types of Water Hardness:

Temporary Hardness

Permanent Hardness

Temporary hardness is due to the presence of bicarbonate ions and can be removed by boiling the water. On the other hand, permanent hardness is due to the presence of calcium and magnesium sulphate and chloride ions, which cannot be removed by boiling.

Calculation of Degree of Hardness of Water:

The degree of hardness of water can be calculated using the following formula:

Degree of Hardness = (Concentration of Ca2+ ions + Concentration of Mg2+ ions) x 50

Here, the concentration of Ca2+ and Mg2+ ions is measured in terms of mg/L or ppm.

Calculation of Degree of Hardness for given Sample:

Given, the sample of water contains 12mg of MgSo4 per kg of water.

The molecular weight of MgSo4 is 120.4 g/mol.

Therefore, the concentration of Mg2+ ions in the sample can be calculated as follows:

Concentration of Mg2+ ions = (12 mg/kg x 1000 g/kg) / (120.4 g/mol x 10^-3 kg/mol)

Concentration of Mg2+ ions = 99.5 mg/L or ppm

As there is no information given about the concentration of Ca2+ ions in the sample, we cannot calculate the degree of hardness of water for the given sample.

Conclusion:

In order to calculate the degree of hardness of water, the concentration of both calcium and magnesium ions needs to be known. Therefore, the degree of hardness of water for the given sample cannot be calculated with the given information.

Answer

We can calculate the degree of hardness by the help of CaCo3..

Explanation:-
To calculate the hardness if 12 mg of Mgso4 present in 1 kg of water...

Given ,

1000g of water contains Mgso4 = 12mg
1000x1000g of water contains MgSo4
= 12 x 1000.
= 12000mg
= 12g.
(1000000 is 1ppm)
1 mole of mgso4 = 1 mole of caco3
120 g of mgso4 = 100g of caco3
12g of mgso4 = (100g * 12 g ) / 120 g of caco3
= 10g of caco3 .

So, here degree of hardness = 10ppm

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