A school flagpole which is 69 m high casts a shadow of 3.2 m at about ...
Given that the time is the same we will also assume that the magnification is the same.
The formula to obtain this is :
Image height of the pole / height of the pole = Image height of the tower/ height of the tower
Let the height of the tower be h .
Doing the substitution we have :
3.2/69 = 18/h
we need h.
3.2h = 1242
h = 1242/3.2 = 388.125 m
= 388.125m
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A school flagpole which is 69 m high casts a shadow of 3.2 m at about ...
Problem Statement:
A school flagpole, which is 69 m high, casts a shadow of 3.2 m at about 11 a.m. The shadow cast by the school tower at the same time is 18 m long. Calculate the height of the tower.
Solution:
To find the height of the tower, we can use the concept of similar triangles.
Step 1: Identify the Similar Triangles
We have two triangles in this problem: the triangle formed by the flagpole, its shadow, and the ground, and the triangle formed by the tower, its shadow, and the ground.
Step 2: Set up the Proportions
Since the two triangles are similar, we can set up a proportion using their corresponding sides.
Let's assume the height of the tower is 'x' meters.
For the flagpole triangle, the height is 69 m and the shadow is 3.2 m. The corresponding sides for the tower triangle are 'x' meters and 18 m.
We can set up the following proportion:
69/3.2 = x/18
Step 3: Solve the Proportion
To solve the proportion, we can cross-multiply and then divide:
3.2x = 69 * 18
3.2x = 1242
Dividing both sides by 3.2, we get:
x = 1242/3.2
x ≈ 387.75
Therefore, the height of the tower is approximately 387.75 meters.
Conclusion:
The height of the tower is approximately 387.75 meters.
A school flagpole which is 69 m high casts a shadow of 3.2 m at about ...
388.125 meter