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A shift reduce parser carries out the actions specified within braces immediately after reducing with the corresponding rule of grammar S—-> xxW ( PRINT “1”) S—-> y { print ” 2 ” } S—-> Sz { print ” 3 ” ) What is the translation of xxxxyzz using the syntax directed translation scheme described by the above rules ?
  • a)
    23131
  • b)
    11233
  • c)
    11231
  • d)
    33211
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A shift reduce parser carries out the actions specified within braces ...
 Initially 2 is printed then 3 then 1 3 1
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A shift reduce parser carries out the actions specified within braces ...
Understanding the Shift-Reduce Parser
The shift-reduce parser processes the input string `xxxxyzz` according to the specified grammar rules. The rules dictate how to reduce the string and perform actions at each reduction step.
Grammar Rules
1. S -> xxW { PRINT "1" }
2. S -> y { PRINT "2" }
3. S -> Sz { PRINT "3" }
Input Analysis
The input string is `xxxxyzz`.
Step-by-Step Reduction
1. Shift 'x' (1st x):
Stack: `x`
Remaining Input: `xxxyzz`
2. Shift 'x' (2nd x):
Stack: `xx`
Remaining Input: `xzyzz`
3. Shift 'x' (3rd x):
Stack: `xxx`
Remaining Input: `yzz`
4. Shift 'x' (4th x):
Stack: `xxxx`
Remaining Input: `zz`
5. Shift 'y':
Stack: `xxxxy`
Remaining Input: `z`
6. Reduce using S -> y:
Stack: `xxxx` + S (y)
Action: PRINT "2"
Remaining Input: `z`
7. Shift 'z':
Stack: `xxxxz`
Remaining Input: ``
8. Reduce using S -> xxW:
Stack: `xx` (from `xxxx`)
Action: PRINT "1"
Remaining Input: `zz`
9. Shift 'z':
Stack: `xxz`
Remaining Input: `z`
10. Shift 'z':
Stack: `xxzz`
Remaining Input: ``
11. Reduce using S -> Sz:
Stack: `x` + z (from `xxz`)
Action: PRINT "3"
Remaining Input: ``
12. Final Reduction: Complete with `S -> Sz`
Action: PRINT "3"
Final Output Sequence
The printed output in order is: "2", "1", "3", "3".
Thus, the final translation for `xxxxyzz` is 23131, confirming that option 'A' is indeed correct.
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