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Number of solutions of the equation tan x + sec x= 2 cosx lying in the interval [0, 2π] is :   (1993)
  • a)
    0
  • b)
    1
  • c)
    2
  • d)
    3
Correct answer is option 'C'. Can you explain this answer?
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Understanding the Equation
The given equation is:
tan x + sec x = 2 cos x
To analyze the solutions, we can rewrite the trigonometric functions in terms of sine and cosine:
- tan x = sin x / cos x
- sec x = 1 / cos x
Substituting these into the equation gives:
sin x / cos x + 1 / cos x = 2 cos x
Rearranging the Equation
Multiplying through by cos x (assuming cos x ≠ 0) leads to:
sin x + 1 = 2 cos^2 x
Using the identity cos^2 x = 1 - sin^2 x, we can rewrite the equation:
sin x + 1 = 2(1 - sin^2 x)
This simplifies to:
2 sin^2 x + sin x - 1 = 0
Finding the Roots
This quadratic equation can be solved using the quadratic formula:
- a = 2, b = 1, c = -1
The discriminant (D) is given by:
D = b^2 - 4ac = 1 + 8 = 9
Since the discriminant is positive, there are two real roots for sin x.
Checking the Interval
To find the values of x, we solve for sin x:
Using the quadratic formula, we find the roots of the equation. The roots will be in the range [-1, 1], as sin x is bounded.
Counting Solutions in the Interval [0, 2π]
For each root of sin x, there will be two corresponding angles in the interval [0, 2π] since sine is positive in the first and second quadrants, and negative in the third and fourth quadrants.
Thus, this leads to a total of two solutions from the roots found.
Conclusion
Therefore, the number of solutions to the equation tan x + sec x = 2 cos x in the interval [0, 2π] is:
Option C: 2
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Number of solutions of the equation tan x + sec x= 2 cosx lying in the interval [0, 2π] is : (1993)a)0b)1c)2d)3Correct answer is option 'C'. Can you explain this answer?
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