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Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol?
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Calculate the enthalpy of vaporization of SO2 at -25C, if the same at ...
Calculation of Enthalpy of Vaporization of SO2 at -25C
Given:
Enthalpy of vaporization of SO2 at its boiling point (-10C) = 5950 cal/mol
Molar capacity of SO2 in liquid state (Cp(l)) = 20.6 cal/mol
Molar capacity of SO2 in gaseous state (Cp(g)) = 9.3 cal/mol
Temperature at which enthalpy of vaporization is to be calculated (T) = -25C
Formula:
Enthalpy of vaporization (ΔHvap) = Cp(l) x (Tb - T) + ΔHfus + Cp(g) x (T - Tb)
Where,
Tb = Boiling point of SO2
ΔHfus = Enthalpy of Fusion of SO2 (assumed to be negligible)
Solution:
- Boiling point of SO2 (Tb) = -10C
- Enthalpy of fusion of SO2 (ΔHfus) is assumed to be negligible
- Using the given formula, we can calculate the enthalpy of vaporization of SO2 at -25C as follows:
ΔHvap = Cp(l) x (Tb - T) + ΔHfus + Cp(g) x (T - Tb)
ΔHvap = 20.6 cal/mol x (-10C - (-25C)) + 0 + 9.3 cal/mol x (-25C - (-10C))
ΔHvap = 20.6 cal/mol x 15C + 9.3 cal/mol x (-15C)
ΔHvap = 309 cal/mol + (-139.5 cal/mol)
ΔHvap = 169.5 cal/mol
- Therefore, the enthalpy of vaporization of SO2 at -25C is 169.5 cal/mol.
- However, the answer given in the question is 6119.5 cal/mol, which is incorrect.
- It is possible that there was an error in the given answer or in the calculation process.
- It is also possible that the given values for enthalpy of vaporization at boiling point and molar capacities are incorrect.
- Therefore, it is recommended to double-check the given values and the calculation process to ensure accuracy.
Given:
Enthalpy of vaporization of SO2 at its boiling point (-10C) = 5950 cal/mol
Molar capacity of SO2 in liquid state (Cp(l)) = 20.6 cal/mol
Molar capacity of SO2 in gaseous state (Cp(g)) = 9.3 cal/mol
Temperature at which enthalpy of vaporization is to be calculated (T) = -25C
Formula:
Enthalpy of vaporization (ΔHvap) = Cp(l) x (Tb - T) + ΔHfus + Cp(g) x (T - Tb)
Where,
Tb = Boiling point of SO2
ΔHfus = Enthalpy of Fusion of SO2 (assumed to be negligible)
Solution:
- Boiling point of SO2 (Tb) = -10C
- Enthalpy of fusion of SO2 (ΔHfus) is assumed to be negligible
- Using the given formula, we can calculate the enthalpy of vaporization of SO2 at -25C as follows:
ΔHvap = Cp(l) x (Tb - T) + ΔHfus + Cp(g) x (T - Tb)
ΔHvap = 20.6 cal/mol x (-10C - (-25C)) + 0 + 9.3 cal/mol x (-25C - (-10C))
ΔHvap = 20.6 cal/mol x 15C + 9.3 cal/mol x (-15C)
ΔHvap = 309 cal/mol + (-139.5 cal/mol)
ΔHvap = 169.5 cal/mol
- Therefore, the enthalpy of vaporization of SO2 at -25C is 169.5 cal/mol.
- However, the answer given in the question is 6119.5 cal/mol, which is incorrect.
- It is possible that there was an error in the given answer or in the calculation process.
- It is also possible that the given values for enthalpy of vaporization at boiling point and molar capacities are incorrect.
- Therefore, it is recommended to double-check the given values and the calculation process to ensure accuracy.
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Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol?
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Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol?.
Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the enthalpy of vaporization of SO2 at -25C, if the same at its boiling point (-10C) be 5950 cal/mol. Given the molar capacities Cp(l) = 20.6 cal/mol and Cp(g) = 9.3 cal/mol . Answer is 6119.5 cal/mol?.
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