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105 ml of pure water at 4°C saturated with NH3 gas yielded a solution of density 0.9 g/ml and containing 30% NH by mass. Find the valume of resulting NH3 solution.           
  • a)
    66.67 ml                           
  • b)
    166.67 ml                         
  • c)
    133.33 ml                         
  • d)
    266.67 ml
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
105 ml of pure water at 4°C saturated with NH3 gas yielded a solut...
Given -
volume of water = 105 mL
density of solution = 0.9 g/mL
Calculation -
Since ammonia dissolved in water is 30% by weight, then using mass % formula, we can calculate the amount of ammonia in water
At 4 degree C, density of water  = 0.999 g/mL
since density = mass /volume
0.999  = mass/ 105 
mass of water = 104.895 g
​now, let mass of ammonia be x.
30x + 3146.85 = 100x
70x = 3146.85
x = 44.955 g
Thus, ammonia dissolved in 105 mL water is 44.955 g
Therefore, total mass of solution = mass of ammonia + mass of water
Mass of solution = 44.955 + 104.895
Mass of solution = 149.85 g
So,density of solution = mass of solution / volume of solution
​0.9 g/mL  = 149.85 g / Volume of solution
Volume of solution = 149.85/ 0.9
Volume of solution = 166.5 mL
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Most Upvoted Answer
105 ml of pure water at 4°C saturated with NH3 gas yielded a solut...
Given -
volume of water = 105 mL
density of solution = 0.9 g/mL
Calculation -
Since ammonia dissolved in water is 30% by weight, then using mass % formula, we can calculate the amount of ammonia in water

At 4 degree C, density of water  = 0.999 g/mL
since density = mass /volume
0.999  = mass/ 105 
mass of water = 104.895 g
​now, let mass of ammonia be x.

30x + 3146.85 = 100x
70x = 3146.85
x = 44.955 g
Thus, ammonia dissolved in 105 mL water is 44.955 g
Therefore, total mass of solution = mass of ammonia + mass of water
Mass of solution = 44.955 + 104.895
Mass of solution = 149.85 g
So,density of solution = mass of solution / volume of solution
​0.9 g/mL  = 149.85 g / Volume of solution
Volume of solution = 149.85/ 0.9
Volume of solution = 166.5 mL
Free Test
Community Answer
105 ml of pure water at 4°C saturated with NH3 gas yielded a solut...
Given -
volume of water = 105 mL
density of solution = 0.9 g/mL
Calculation -
Since ammonia dissolved in water is 30% by weight, then using mass % formula, we can calculate the amount of ammonia in water
At 4 degree C, density of water  = 0.999 g/mL
since density = mass /volume
0.999  = mass/ 105 
mass of water = 104.895 g
​now, let mass of ammonia be x.
30x + 3146.85 = 100x
70x = 3146.85
x = 44.955 g
Thus, ammonia dissolved in 105 mL water is 44.955 g
Therefore, total mass of solution = mass of ammonia + mass of water
Mass of solution = 44.955 + 104.895
Mass of solution = 149.85 g
So,density of solution = mass of solution / volume of solution
​0.9 g/mL  = 149.85 g / Volume of solution
Volume of solution = 149.85/ 0.9
Volume of solution = 166.5 mL
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Question Description
105 ml of pure water at 4°C saturated with NH3 gas yielded a solution of density 0.9 g/ml and containing 30% NH by mass. Find the valume of resulting NH3 solution.a)66.67 mlb)166.67 mlc)133.33 mld)266.67 mlCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 105 ml of pure water at 4°C saturated with NH3 gas yielded a solution of density 0.9 g/ml and containing 30% NH by mass. Find the valume of resulting NH3 solution.a)66.67 mlb)166.67 mlc)133.33 mld)266.67 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 105 ml of pure water at 4°C saturated with NH3 gas yielded a solution of density 0.9 g/ml and containing 30% NH by mass. Find the valume of resulting NH3 solution.a)66.67 mlb)166.67 mlc)133.33 mld)266.67 mlCorrect answer is option 'B'. Can you explain this answer?.
Solutions for 105 ml of pure water at 4°C saturated with NH3 gas yielded a solution of density 0.9 g/ml and containing 30% NH by mass. Find the valume of resulting NH3 solution.a)66.67 mlb)166.67 mlc)133.33 mld)266.67 mlCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
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