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The following equations are balanced atomwise and chargewise.
(i) Cr2O72- + 8H+ + 2H202 → 2Cr3+ + 7H20 + 202
(ii) Cr2072- + 8H+ + 5H202→ 2Cr3+ + 9H20 + 402
(iii) Cr2072- + 8H+ + 7H202→ 2Cr+ + 11H20 + 502
The precise equationlequations representing the oxidation of H202 is/are
- a)(i) only
- b)(ii) only
- c)(iii) only
- d)all the three
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The following equations are balanced atomwise and chargewise.(i) Cr2O...
The correct answer is option A
Cr2O72- converts into Cr3+ in acidic medium I.e. in H+ medium.
First balance the Cr atom on both sides and then Oxygen atom. H+ is in excess due to acidic medium.
Add H+ as +ve charge to balance the charge on both sides.
Cr2O72- converts into Cr3+ in acidic medium I.e. in H+ medium.
First balance the Cr atom on both sides and then Oxygen atom. H+ is in excess due to acidic medium.
Add H+ as +ve charge to balance the charge on both sides.
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Community Answer
The following equations are balanced atomwise and chargewise.(i) Cr2O...
See Cr2O7^2- converts into Cr3+ in acidic medium I.e. in H+ medium.
First balance Cr atom both sides and then Oxygen atom . H+ is in excess due to acidic medium.
Add H+ as +ve charge to balance the charge on both sides.
First balance Cr atom both sides and then Oxygen atom . H+ is in excess due to acidic medium.
Add H+ as +ve charge to balance the charge on both sides.
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The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer?.
The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer?.
Solutions for The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The following equations are balanced atomwise and chargewise.(i) Cr2O72- + 8H+ + 2H202 →2Cr3+ + 7H20 + 202(ii)Cr2072- + 8H+ + 5H202→2Cr3+ + 9H20 + 402(iii)Cr2072- + 8H+ + 7H202→2Cr+ + 11H20 + 502The precise equationlequations representing the oxidation of H202 is/area)(i) onlyb)(ii) onlyc)(iii) onlyd)all the threeCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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