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The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared
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the Class 11 exam syllabus. Information about The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer?.
Solutions for The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 gm of a copper(II) salt was dissolved in water and added to, an excess of potassium iodide solution liberating iodine according to the following equation2Cu2 (aq) + 4I– (aq) 2CuI(s) + I2(aq)The iodine liberated required 24.5cm3 of a 0.100 mole dm-3 solution of sodium thiosulphate2S2032- (aq) + I2(aq) →2I– (aq) + S4062- (aq)the percentage of copper, by mass in the copper (ll) salt is. [Atomic mass of copper = 63.5]a)64.2b)51.0c)48.4d)25.5Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.