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KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are
1. I03– + I– →I2 (valency factor = 5/3)
2. I2 + S2032– → S4062– + I– (valency factor = 2)
meq of hypo = meq of I2 = meq of I03– + meq of I–
I03– react with I– ⇒ meq of I03– = meq of I–
Statement-1 : meq of hypo = 2 x meq of I03–
Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequence
- a)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.
- b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.
- c)Statement-2 is True, Statement-2 is False.
- d)Statement-1 is False, Statement-2 is True.
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
KIO3 reacts with KI to liberate iodine and liberated Iodine is titrate...
The correct answer is option A
Milliequivalent of IO3− is equal to milliequivalent of I−.
Milliequivalent of hypo is equal to milliequivalent of IO3− plus milliequivalent of I−.
The milliequivalent of hypo is twice the milliequivalent of IO3−. It is also twice the milliequivalent of I−.
Milliequivalent of IO3− is equal to milliequivalent of I−.
Milliequivalent of hypo is equal to milliequivalent of IO3− plus milliequivalent of I−.
The milliequivalent of hypo is twice the milliequivalent of IO3−. It is also twice the milliequivalent of I−.
Most Upvoted Answer
KIO3 reacts with KI to liberate iodine and liberated Iodine is titrate...
Statement Analysis:
Statement-1: meq of hypo = 2 x meq of I03
Statement-2: valency factor of I2 in both the equations are different, therefore we cannot equate milliequivalents in sequence.
Explanation:
- In the given reaction, KIO3 reacts with KI to liberate iodine.
- The liberated iodine is titrated with standard hypo solution.
- The reactions involved in the process are as follows:
I03 I I2 (valency factor = 5/3)
I2 S2032 S4062 I (valency factor = 2)
- The meq of hypo is equal to the meq of I2, which is also equal to the meq of I03.
- From the first equation, we can see that the valency factor of I2 is 2/5 times the valency factor of I03. Hence, the meq of I03 is 5/2 times the meq of I2.
- Therefore, Statement-1 is true. meq of hypo = 2 x meq of I03.
- Statement-2 is also true. The valency factor of I2 in both equations is different, and hence we cannot equate milliequivalents in sequence.
- Statement-2 is also a correct explanation for Statement-1.
- Therefore, the correct answer is option A.
Summary:
- The meq of hypo is equal to the meq of I2, which is also equal to the meq of I03.
- The valency factor of I2 in both equations is different, and hence we cannot equate milliequivalents in sequence.
- Statement-1 is true. meq of hypo = 2 x meq of I03.
- Statement-2 is also true and is a correct explanation for Statement-1.
- Therefore, the correct answer is option A.
Statement-1: meq of hypo = 2 x meq of I03
Statement-2: valency factor of I2 in both the equations are different, therefore we cannot equate milliequivalents in sequence.
Explanation:
- In the given reaction, KIO3 reacts with KI to liberate iodine.
- The liberated iodine is titrated with standard hypo solution.
- The reactions involved in the process are as follows:
I03 I I2 (valency factor = 5/3)
I2 S2032 S4062 I (valency factor = 2)
- The meq of hypo is equal to the meq of I2, which is also equal to the meq of I03.
- From the first equation, we can see that the valency factor of I2 is 2/5 times the valency factor of I03. Hence, the meq of I03 is 5/2 times the meq of I2.
- Therefore, Statement-1 is true. meq of hypo = 2 x meq of I03.
- Statement-2 is also true. The valency factor of I2 in both equations is different, and hence we cannot equate milliequivalents in sequence.
- Statement-2 is also a correct explanation for Statement-1.
- Therefore, the correct answer is option A.
Summary:
- The meq of hypo is equal to the meq of I2, which is also equal to the meq of I03.
- The valency factor of I2 in both equations is different, and hence we cannot equate milliequivalents in sequence.
- Statement-1 is true. meq of hypo = 2 x meq of I03.
- Statement-2 is also true and is a correct explanation for Statement-1.
- Therefore, the correct answer is option A.
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Community Answer
KIO3 reacts with KI to liberate iodine and liberated Iodine is titrate...
The correct answer is option A
Milliequivalent of IO3− is equal to milliequivalent of I−.
Milliequivalent of hypo is equal to milliequivalent of IO3− plus milliequivalent of I−.
The milliequivalent of hypo is twice the milliequivalent of IO3−. It is also twice the milliequivalent of I−.
Milliequivalent of IO3− is equal to milliequivalent of I−.
Milliequivalent of hypo is equal to milliequivalent of IO3− plus milliequivalent of I−.
The milliequivalent of hypo is twice the milliequivalent of IO3−. It is also twice the milliequivalent of I−.
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KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer?
Question Description
KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer?.
KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer?.
Solutions for KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice KIO3 reacts with KI to liberate iodine and liberated Iodine is titrated with standard hypo solution, The reactions are1. I03– + I– →I2 (valency factor = 5/3)2. I2 + S2032– →S4062– + I– (valency factor = 2)meq of hypo = meq of I2 = meq of I03– + meq of I–I03– react with I– ⇒meq of I03– = meq of I–Statement-1 : meq of hypo = 2 x meq of I03–Statement-2 : valency factor of I2 in both the equation are different therefore we cannot equate milliequivalents in sequencea)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-2.b)Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-2.c)Statement-2 is True, Statement-2 is False.d)Statement-1 is False, Statement-2 is True.Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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