Class 11 Exam > Class 11 Questions > Statement I : 2-bromobutane with (CH3)3COK in...
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Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.
Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.
Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.
- a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
- b)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I
- c)Statement I is correct but Statement II is incorrect
- d)Statement II is correct but Statement I is incorrect
Correct answer is option 'B'. Can you explain this answer?
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Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1...
Statement I: 2-bromobutane with (CH3)3COK in tertiary butanol gives 1-butene as the major product.
Statement II: Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.
Explanation:
E-2 elimination reaction is a type of elimination reaction in which a base removes a proton from the β-carbon of a leaving group, resulting in the formation of a double bond.
When 2-bromobutane reacts with (CH3)3COK in tertiary butanol, the strong base (CH3)3COK abstracts a proton from the β-carbon of 2-bromobutane. This leads to the formation of a carbanion intermediate. The carbanion then undergoes elimination of the bromide ion to form a double bond, resulting in the formation of 1-butene.
Now let's analyze each statement separately:
Statement I: 2-bromobutane with (CH3)3COK in tertiary butanol gives 1-butene as the major product.
This statement is correct. When 2-bromobutane reacts with (CH3)3COK in tertiary butanol, the major product formed is 1-butene. This is because the strong base (CH3)3COK favors the E-2 elimination reaction, which results in the formation of a double bond.
Statement II: Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.
This statement is also correct. (CH3)3COK is a very strong base and is capable of abstracting a proton from the β-carbon of a leaving group. In this case, the leaving group is the bromide ion in 2-bromobutane. The strong base (CH3)3COK in tertiary butanol brings about the E-2 elimination reaction by removing the proton and forming a double bond.
Explanation of the relationship between the two statements:
Statement II is the correct explanation of Statement I. The very strong base (CH3)3COK in tertiary butanol brings about the E-2 elimination reaction, which results in the formation of 1-butene as the major product. Therefore, both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I.
In conclusion, both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I.
Statement II: Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.
Explanation:
E-2 elimination reaction is a type of elimination reaction in which a base removes a proton from the β-carbon of a leaving group, resulting in the formation of a double bond.
When 2-bromobutane reacts with (CH3)3COK in tertiary butanol, the strong base (CH3)3COK abstracts a proton from the β-carbon of 2-bromobutane. This leads to the formation of a carbanion intermediate. The carbanion then undergoes elimination of the bromide ion to form a double bond, resulting in the formation of 1-butene.
Now let's analyze each statement separately:
Statement I: 2-bromobutane with (CH3)3COK in tertiary butanol gives 1-butene as the major product.
This statement is correct. When 2-bromobutane reacts with (CH3)3COK in tertiary butanol, the major product formed is 1-butene. This is because the strong base (CH3)3COK favors the E-2 elimination reaction, which results in the formation of a double bond.
Statement II: Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.
This statement is also correct. (CH3)3COK is a very strong base and is capable of abstracting a proton from the β-carbon of a leaving group. In this case, the leaving group is the bromide ion in 2-bromobutane. The strong base (CH3)3COK in tertiary butanol brings about the E-2 elimination reaction by removing the proton and forming a double bond.
Explanation of the relationship between the two statements:
Statement II is the correct explanation of Statement I. The very strong base (CH3)3COK in tertiary butanol brings about the E-2 elimination reaction, which results in the formation of 1-butene as the major product. Therefore, both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I.
In conclusion, both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I.
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Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1...
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Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?
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Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?.
Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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ample number of questions to practice Statement I : 2-bromobutane with (CH3)3COK in tertiary butanol gives 1 -butene as major product.Statement II : Very strong base (CH3)3COK in tertiary butanol brings about E-2 elimination reaction.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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