Class 11 Exam > Class 11 Questions > Statement I : Treatment of either 1,2-dibromo...
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Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.
Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.
- a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
- b)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I
- c)Statement I is correct but Statement II is incorrect
- d)Statement II is incorrect but Statement I incorrect
Correct answer is option 'A'. Can you explain this answer?
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Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobuta...
Statement I: Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.
Statement II: NaNH2 forms salt with terminal alkyne which makes possible the above observation.
To understand the correctness of the statements and the explanation provided, let's analyze each statement individually.
Statement I: Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.
When 1,2-dibromobutane or 2,2-dibromobutane is treated with NaNH2, both compounds undergo an elimination reaction known as the dehydrohalogenation reaction. In this reaction, the bromine atoms are eliminated from the alkyl halide, resulting in the formation of an alkyne. Both 1,2-dibromobutane and 2,2-dibromobutane have the same carbon skeleton, and thus, they will give the same product, 1-butyne. Therefore, Statement I is correct.
Statement II: NaNH2 forms salt with terminal alkyne which makes possible the above observation.
NaNH2 is a strong base and can react with terminal alkynes to form a salt known as a sodium acetylide. This reaction involves the deprotonation of the terminal hydrogen atom of the alkyne by NaNH2. The resulting sodium acetylide can then react with an alkyl halide through an SN2 reaction, resulting in the formation of an alkyne. In this case, NaNH2 reacts with the alkyl halide derived from either 1,2-dibromobutane or 2,2-dibromobutane to form the sodium acetylide, which then eliminates bromine atoms to give 1-butyne. Therefore, Statement II is correct.
Explanation: Statement II provides the correct explanation for Statement I. The formation of a sodium acetylide salt with NaNH2 allows the elimination of bromine atoms from the alkyl halide, resulting in the formation of 1-butyne. The deprotonation of the terminal hydrogen atom in the alkyne by the strong base NaNH2 is a key step in this process. Thus, the correct answer is option A: Both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I.
Statement II: NaNH2 forms salt with terminal alkyne which makes possible the above observation.
To understand the correctness of the statements and the explanation provided, let's analyze each statement individually.
Statement I: Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.
When 1,2-dibromobutane or 2,2-dibromobutane is treated with NaNH2, both compounds undergo an elimination reaction known as the dehydrohalogenation reaction. In this reaction, the bromine atoms are eliminated from the alkyl halide, resulting in the formation of an alkyne. Both 1,2-dibromobutane and 2,2-dibromobutane have the same carbon skeleton, and thus, they will give the same product, 1-butyne. Therefore, Statement I is correct.
Statement II: NaNH2 forms salt with terminal alkyne which makes possible the above observation.
NaNH2 is a strong base and can react with terminal alkynes to form a salt known as a sodium acetylide. This reaction involves the deprotonation of the terminal hydrogen atom of the alkyne by NaNH2. The resulting sodium acetylide can then react with an alkyl halide through an SN2 reaction, resulting in the formation of an alkyne. In this case, NaNH2 reacts with the alkyl halide derived from either 1,2-dibromobutane or 2,2-dibromobutane to form the sodium acetylide, which then eliminates bromine atoms to give 1-butyne. Therefore, Statement II is correct.
Explanation: Statement II provides the correct explanation for Statement I. The formation of a sodium acetylide salt with NaNH2 allows the elimination of bromine atoms from the alkyl halide, resulting in the formation of 1-butyne. The deprotonation of the terminal hydrogen atom in the alkyne by the strong base NaNH2 is a key step in this process. Thus, the correct answer is option A: Both Statement I and Statement II are correct, and Statement II is the correct explanation of Statement I.
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Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer?
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Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer?.
Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Statement I : Treatment of either 1,2-dibromobutane or 2,2-dibromobutane with NaNH2 gives the same 1-butyne.Statement II : NaNH2 forms salt with terminal alkyne which makes possible the above observation.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement I incorrectCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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