Class 11 Exam  >  Class 11 Questions  >  Energy of the electron in nth orbit is given ... Start Learning for Free
Energy of the electron in nth orbit is given by E   Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0 x 108ms -1)
[AIEEE 2012]
  • a)
    1.216x 10-7 m
  • b)
    2.816x 10-7 m
  • c)
    6.500x 10-7 m
  • d)
    8.500x 10-7 m
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Energy of the electron in nth orbit is given by E Wavelength of light ...
Explore Courses for Class 11 exam

Top Courses for Class 11

Question Description
Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Energy of the electron in nth orbit is given by E Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0x 108ms -1)[AIEEE 2012]a)1.216x 10-7 mb)2.816x 10-7 mc)6.500x 10-7 md)8.500x 10-7 mCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
Explore Courses for Class 11 exam

Top Courses for Class 11

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev