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Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H– is:
Correct answer is '3'. Can you explain this answer?
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Not considering the electronic spin, the degeneracy of the second exci...
+ ion (n = 3) is 4.
The degeneracy of an energy level (state) is the number of different ways that the same energy can be obtained. For the H atom, the second excited state (n = 3) has three possible values of l (l = 0, 1, 2), which correspond to the s, p, and d subshells. Each subshell has a different value of m, which can range from -l to +l. Therefore, the degeneracy of the second excited state of H atom is:
Degeneracy = (2s+1) + (2p+1) + (2d+1) = 1 + 3 + 5 = 9
For the H+ ion, there is only one electron, so there is no need to consider the electron-electron repulsion. The energy levels are determined only by the principal quantum number (n) and the total angular momentum quantum number (j), which is the sum of the orbital angular momentum (l) and the spin angular momentum (s). For n = 3, the possible values of j are 3/2 and 1/2, corresponding to the two possible values of l (l = 1 and 0, respectively). Each value of j has a degeneracy of 2j+1. Therefore, the degeneracy of the second excited state of H+ ion is:
Degeneracy = (2j1+1) + (2j2+1) = (2(3/2)+1) + (2(1/2)+1) = 4
The degeneracy of an energy level (state) is the number of different ways that the same energy can be obtained. For the H atom, the second excited state (n = 3) has three possible values of l (l = 0, 1, 2), which correspond to the s, p, and d subshells. Each subshell has a different value of m, which can range from -l to +l. Therefore, the degeneracy of the second excited state of H atom is:
Degeneracy = (2s+1) + (2p+1) + (2d+1) = 1 + 3 + 5 = 9
For the H+ ion, there is only one electron, so there is no need to consider the electron-electron repulsion. The energy levels are determined only by the principal quantum number (n) and the total angular momentum quantum number (j), which is the sum of the orbital angular momentum (l) and the spin angular momentum (s). For n = 3, the possible values of j are 3/2 and 1/2, corresponding to the two possible values of l (l = 1 and 0, respectively). Each value of j has a degeneracy of 2j+1. Therefore, the degeneracy of the second excited state of H+ ion is:
Degeneracy = (2j1+1) + (2j2+1) = (2(3/2)+1) + (2(1/2)+1) = 4
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Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H– is:Correct answer is '3'. Can you explain this answer?
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Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H– is:Correct answer is '3'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H– is:Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H– is:Correct answer is '3'. Can you explain this answer?.
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