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The increasing order of the ionic radii of the given isoelectronic species is:
  • a)
    Ca2+, K+, Cl-, S2-
  • b)
    K+, S2-, Ca2+, Cl-
  • c)
     Cl-, Ca2+, K+, S2-
  • d)
    S2-, Cl-, Ca2+, K+
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The increasing order of the ionic radii of the given isoelectronic spe...
For isoelectronic species, as the z/e decreases, ionic radius increases
such as ionic radii ∝ 1/z.
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Most Upvoted Answer
The increasing order of the ionic radii of the given isoelectronic spe...
For isoelectronic species, as the z/e decreases, ionic radius increases
such as ionic radii ∝ 1/z.
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Community Answer
The increasing order of the ionic radii of the given isoelectronic spe...
The correct answer is A because cations have a smaller size than the parent atom due to the effective nuclear charge
Ca2+ losses two electrons hence has the smallest size whereas S2- gains 2 electrons and has the largest size due to the repulsion created due to addition of two electrons


Hope this explains it
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The increasing order of the ionic radii of the given isoelectronic species is:a)Ca2+, K+, Cl-, S2-b)K+, S2-, Ca2+, Cl-c)Cl-, Ca2+, K+, S2-d)S2-, Cl-, Ca2+, K+Correct answer is option 'A'. Can you explain this answer?
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The increasing order of the ionic radii of the given isoelectronic species is:a)Ca2+, K+, Cl-, S2-b)K+, S2-, Ca2+, Cl-c)Cl-, Ca2+, K+, S2-d)S2-, Cl-, Ca2+, K+Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The increasing order of the ionic radii of the given isoelectronic species is:a)Ca2+, K+, Cl-, S2-b)K+, S2-, Ca2+, Cl-c)Cl-, Ca2+, K+, S2-d)S2-, Cl-, Ca2+, K+Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The increasing order of the ionic radii of the given isoelectronic species is:a)Ca2+, K+, Cl-, S2-b)K+, S2-, Ca2+, Cl-c)Cl-, Ca2+, K+, S2-d)S2-, Cl-, Ca2+, K+Correct answer is option 'A'. Can you explain this answer?.
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