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The molecules that will have dipole moment are
- a)2, 2-dimethyl propane
- b)frans-2-pentene
- c)cis-3-hexene
- d)2, 2, 3, 3-tetramethyl butane
Correct answer is option 'B,C'. Can you explain this answer?
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Dipole moment is a measure of the polarity of a molecule. A molecule will have a dipole moment if there is an uneven distribution of charge due to differences in electronegativity between the atoms.
The molecules that will have a dipole moment in this case are:
b) frans-2-pentene
c) cis-3-hexene
Explanation:
b) frans-2-pentene
In frans-2-pentene, the molecule has a double bond between two carbon atoms. The carbon atoms are sp2 hybridized and have a trigonal planar geometry. The two methyl groups and the two hydrogen atoms are attached to the carbon atoms. The double bond creates a region of higher electron density between the carbon atoms, which makes that region slightly negative. The methyl groups and hydrogen atoms create regions of lower electron density, making those regions slightly positive. This uneven distribution of charge creates a dipole moment in the molecule.
c) cis-3-hexene
In cis-3-hexene, the molecule also has a double bond between two carbon atoms. The carbon atoms are sp2 hybridized and have a trigonal planar geometry. The three hydrogen atoms are attached to the carbon atoms, and there is a methyl group attached to one of the carbon atoms. Similar to frans-2-pentene, the double bond creates a region of higher electron density between the carbon atoms, making that region slightly negative. The hydrogen atoms create regions of lower electron density, making those regions slightly positive. The presence of the methyl group adds to the uneven distribution of charge, creating a dipole moment in the molecule.
The other molecules listed, 2, 2-dimethyl propane and 2, 2, 3, 3-tetramethyl butane, do not have a dipole moment because they do not have any polar bonds. In these molecules, the carbon atoms are all sp3 hybridized and have a tetrahedral geometry. The presence of the methyl groups does not create any significant differences in electronegativity, resulting in an even distribution of charge and no dipole moment.
In summary, frans-2-pentene and cis-3-hexene have a dipole moment due to the presence of polar double bonds and the uneven distribution of charge caused by the attached groups. 2, 2-dimethyl propane and 2, 2, 3, 3-tetramethyl butane do not have a dipole moment because they lack any polar bonds.
The molecules that will have a dipole moment in this case are:
b) frans-2-pentene
c) cis-3-hexene
Explanation:
b) frans-2-pentene
In frans-2-pentene, the molecule has a double bond between two carbon atoms. The carbon atoms are sp2 hybridized and have a trigonal planar geometry. The two methyl groups and the two hydrogen atoms are attached to the carbon atoms. The double bond creates a region of higher electron density between the carbon atoms, which makes that region slightly negative. The methyl groups and hydrogen atoms create regions of lower electron density, making those regions slightly positive. This uneven distribution of charge creates a dipole moment in the molecule.
c) cis-3-hexene
In cis-3-hexene, the molecule also has a double bond between two carbon atoms. The carbon atoms are sp2 hybridized and have a trigonal planar geometry. The three hydrogen atoms are attached to the carbon atoms, and there is a methyl group attached to one of the carbon atoms. Similar to frans-2-pentene, the double bond creates a region of higher electron density between the carbon atoms, making that region slightly negative. The hydrogen atoms create regions of lower electron density, making those regions slightly positive. The presence of the methyl group adds to the uneven distribution of charge, creating a dipole moment in the molecule.
The other molecules listed, 2, 2-dimethyl propane and 2, 2, 3, 3-tetramethyl butane, do not have a dipole moment because they do not have any polar bonds. In these molecules, the carbon atoms are all sp3 hybridized and have a tetrahedral geometry. The presence of the methyl groups does not create any significant differences in electronegativity, resulting in an even distribution of charge and no dipole moment.
In summary, frans-2-pentene and cis-3-hexene have a dipole moment due to the presence of polar double bonds and the uneven distribution of charge caused by the attached groups. 2, 2-dimethyl propane and 2, 2, 3, 3-tetramethyl butane do not have a dipole moment because they lack any polar bonds.
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The molecules that will have dipole moment area)2, 2-dimethyl propaneb)frans-2-pentenec)cis-3-hexened)2, 2, 3, 3-tetramethyl butaneCorrect answer is option 'B,C'. Can you explain this answer?
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