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A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.
Thus, vapour pressure of water is
- a)23.86 mm
- b)652.13 mm
- c)676 mm
- d)736.14 mm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A chemist decides to find the vapour pressure of water by the gas satu...
Given:
- Initial weight of water = 65.44 g
- Final weight of water = 63.13 g
- Volume of N2 gas passed = 100 L
- Temperature of water = 298 K
To find:
Vapour pressure of water
Solution:
Step 1: Calculate the moles of N2 gas passed
The volume of N2 gas passed is given as 100 L. Since the gas is at room temperature and pressure, we can use the ideal gas law to calculate the moles of N2 gas.
PV = nRT
Where:
P = pressure (unknown)
V = volume of gas (100 L)
n = moles of gas (unknown)
R = ideal gas constant (0.0821 L atm/mol K)
T = temperature (298 K)
Solving for n, we get:
n = PV / RT
Substituting the given values, we get:
n = (P * 100) / (0.0821 * 298)
Step 2: Calculate the moles of water vaporized
The change in weight of water can be used to calculate the moles of water vaporized.
Initial weight of water = 65.44 g
Final weight of water = 63.13 g
Change in weight = Initial weight - Final weight
= 65.44 g - 63.13 g
= 2.31 g
Since the molar mass of water is 18 g/mol, we can calculate the moles of water vaporized using the formula:
moles = weight / molar mass
Substituting the given values, we get:
moles = 2.31 g / 18 g/mol
Step 3: Calculate the vapour pressure of water
The vapour pressure of water can be calculated using the formula:
vapour pressure = moles of water vaporized / moles of N2 gas passed
Substituting the calculated values, we get:
vapour pressure = (2.31 g / 18 g/mol) / n
Now, substitute the value of 'n' calculated in Step 1 to get the final answer.
Final Answer:
The vapour pressure of water is approximately 23.86 mm. (Option A)
- Initial weight of water = 65.44 g
- Final weight of water = 63.13 g
- Volume of N2 gas passed = 100 L
- Temperature of water = 298 K
To find:
Vapour pressure of water
Solution:
Step 1: Calculate the moles of N2 gas passed
The volume of N2 gas passed is given as 100 L. Since the gas is at room temperature and pressure, we can use the ideal gas law to calculate the moles of N2 gas.
PV = nRT
Where:
P = pressure (unknown)
V = volume of gas (100 L)
n = moles of gas (unknown)
R = ideal gas constant (0.0821 L atm/mol K)
T = temperature (298 K)
Solving for n, we get:
n = PV / RT
Substituting the given values, we get:
n = (P * 100) / (0.0821 * 298)
Step 2: Calculate the moles of water vaporized
The change in weight of water can be used to calculate the moles of water vaporized.
Initial weight of water = 65.44 g
Final weight of water = 63.13 g
Change in weight = Initial weight - Final weight
= 65.44 g - 63.13 g
= 2.31 g
Since the molar mass of water is 18 g/mol, we can calculate the moles of water vaporized using the formula:
moles = weight / molar mass
Substituting the given values, we get:
moles = 2.31 g / 18 g/mol
Step 3: Calculate the vapour pressure of water
The vapour pressure of water can be calculated using the formula:
vapour pressure = moles of water vaporized / moles of N2 gas passed
Substituting the calculated values, we get:
vapour pressure = (2.31 g / 18 g/mol) / n
Now, substitute the value of 'n' calculated in Step 1 to get the final answer.
Final Answer:
The vapour pressure of water is approximately 23.86 mm. (Option A)
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A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer?.
A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer?.
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A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A chemist decides to find the vapour pressure of water by the gas saturation method . 100 L of N2 gas is passed through 65.44 g of water. After passage of the gas, 63.13 g water remained. The temperature of water is 298 K.Thus, vapour pressure of water isa)23.86 mmb)652.13mmc)676 mmd)736.14mmCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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