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A thin ballon filled with air at 47°C has a volume of 3 litre. If on placing it in a cooled room its volume becomes 2.7 litre, the temperature of room is :
  • a)
    42°
  • b)
    100°C
  • c)
    15°C
  • d)
    200°C
Correct answer is option 'C'. Can you explain this answer?
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A thin ballon filled with air at 47°C has a volume of 3 litre. If...
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A thin ballon filled with air at 47°C has a volume of 3 litre. If...
Given:
Initial volume of the balloon (V1) = 3 litre
Final volume of the balloon (V2) = 2.7 litre

We are required to find the temperature of the room.

The relationship between temperature and volume of a gas is given by the Charles' Law, which states that the volume of a gas is directly proportional to its temperature, provided pressure and moles of gas remain constant.

Mathematically, Charles' Law can be expressed as:
V1/T1 = V2/T2

where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Substituting the given values into the equation, we have:
3/T1 = 2.7/T2

Simplifying the equation, we get:
T2 = (2.7 * T1) / 3

To find the temperature of the room (T2), we need to know the initial temperature of the balloon (T1).

Since the initial temperature is not given, we cannot directly calculate the temperature of the room.

Hence, the given information is insufficient to determine the temperature of the room.

Therefore, none of the options provided (a) 42°C, (b) 100°C, (c) 15°C, or (d) 200°C can be considered as the correct answer.

In conclusion, the question does not have a correct answer among the given options.
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A thin ballon filled with air at 47°C has a volume of 3 litre. If on placing it in a cooled room its volume becomes 2.7 litre, the temperature of room is :a)42°b)100°Cc)15°Cd)200°CCorrect answer is option 'C'. Can you explain this answer?
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