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The critical volume of a gas is 0.072 lit. mo1-1. The radius of the molecule will be, in cm
- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The critical volume of a gas is 0.072 lit. mo1-1. The radius of the mo...
The critical volume of three times the Van der Waals constant 'b'.
b=16/3πr3NA;Vc=3b=0.072 lit. mol−1
The expression for the magnitude of the Van der Waals constant, b, for the gas is b=16/3πr3NA
Thus 3b=16/3πr3NA×3
Substitute values in the above expression,
0.072×1000=16/3×6.023×1023×π×r3×3
Thus r=(3/4π×10−23)1/3cm.
b=16/3πr3NA;Vc=3b=0.072 lit. mol−1
The expression for the magnitude of the Van der Waals constant, b, for the gas is b=16/3πr3NA
Thus 3b=16/3πr3NA×3
Substitute values in the above expression,
0.072×1000=16/3×6.023×1023×π×r3×3
Thus r=(3/4π×10−23)1/3cm.
Most Upvoted Answer
The critical volume of a gas is 0.072 lit. mo1-1. The radius of the mo...
The critical volume of three times the Van der Waals constant 'b'.
b=16/3πr3NA;Vc=3b=0.072 lit. mol−1
The expression for the magnitude of the Van der Waals constant, b, for the gas is b=16/3πr3NA
Thus 3b=16/3πr3NA×3
Substitute values in the above expression,
0.072×1000=16/3×6.023×1023×π×r3×3
Thus r=(3/4π×10−23)1/3cm.
b=16/3πr3NA;Vc=3b=0.072 lit. mol−1
The expression for the magnitude of the Van der Waals constant, b, for the gas is b=16/3πr3NA
Thus 3b=16/3πr3NA×3
Substitute values in the above expression,
0.072×1000=16/3×6.023×1023×π×r3×3
Thus r=(3/4π×10−23)1/3cm.
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The critical volume of a gas is 0.072 lit. mo1-1. The radius of the mo...
Option a is correct
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The critical volume of a gas is 0.072 lit. mo1-1. The radius of the molecule will be, in cma)b)c)d)Correct answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The critical volume of a gas is 0.072 lit. mo1-1. The radius of the molecule will be, in cma)b)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The critical volume of a gas is 0.072 lit. mo1-1. The radius of the molecule will be, in cma)b)c)d)Correct answer is option 'A'. Can you explain this answer?.
The critical volume of a gas is 0.072 lit. mo1-1. The radius of the molecule will be, in cma)b)c)d)Correct answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The critical volume of a gas is 0.072 lit. mo1-1. The radius of the molecule will be, in cma)b)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The critical volume of a gas is 0.072 lit. mo1-1. The radius of the molecule will be, in cma)b)c)d)Correct answer is option 'A'. Can you explain this answer?.
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