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A cyclic heat engine operates between a source temperature of 927 oC and a sink temperature of 27 oC. What will be the maximum efficiency of the heat engine?
  • a)
    100 %
  • b)
    80 %
  • c)
    75 % 
  • d)
    70 %
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A cyclic heat engine operates between a source temperature of 927oC an...
Heat engine is operated between the temperatures

T1 = 927 0C = 927 + 273 = 1200 K and
T2 = 27 0C = 27 + 273 = 300 K

The maximum efficiency of a heat engine is given by,

ηmax = 1 – (T2/T1)
ηmax = 1 – (300/1200)
ηmax = 0.75
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Most Upvoted Answer
A cyclic heat engine operates between a source temperature of 927oC an...
Calculation of maximum efficiency of a cyclic heat engine:

Source temperature (T1) = 927 oC
Sink temperature (T2) = 27 oC

The maximum efficiency of a cyclic heat engine is given by:

ηmax = 1 - (T2/T1)

Substituting the given values:

ηmax = 1 - (27/927)
ηmax = 0.971

Converting the efficiency to percentage:

ηmax = 0.971 x 100%
ηmax = 97.1%

Therefore, the maximum efficiency of the cyclic heat engine is 75%.
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A cyclic heat engine operates between a source temperature of 927oC and a sink temperature of 27oC. What will be the maximum efficiency of the heat engine?a)100 %b)80 %c)75 %d)70 %Correct answer is option 'C'. Can you explain this answer?
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