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Bond dissociation energy of = + 590 kJ mol-1 and that of (C—C) = + 331 kJ mol-1 at 298 K.
Enthalpy change for the polymerisation of ethene to polyethene is (where n is large integral value)
  • a)
    72 kJ mol-1
  • b)
    -72 kJ mol-1
  • c)
    279 kJ mol-1
  • d)
    -279 kJ mol-1
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Bond dissociation energy of = + 590 kJ mol-1 and that of (C—C) ...
The correct answer is option B
During the polymerization of ethylene, one mole of ethylene breaks i.e. one C = C double bond breaks and the two CH2- groups are linked with C-C single bonds thus forming three single bonds. 
But in the whole unit of polymer, number of single C-C bonds formed/mole of ethylene is 2.
Energy due to formation of 2 C-C single bonds = 2 X 331 = 662 kJ/mol. 
 Energy due to dissociation of 1  C = C double bond = 590 kJ/mol. 
Thus, the enthalpy of polymerisation per mole of ethylene at 298 K = (590-662) = -72 kJ/mol
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Most Upvoted Answer
Bond dissociation energy of = + 590 kJ mol-1 and that of (C—C) ...
B
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Bond dissociation energy of = + 590 kJ mol-1 and that of (C—C) = + 331 kJ mol-1 at 298 K.Enthalpy change for the polymerisation of ethene to polyethene is (where n is large integral value)a)72 kJ mol-1b)-72 kJ mol-1c)279 kJ mol-1d)-279 kJ mol-1Correct answer is option 'B'. Can you explain this answer?
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Bond dissociation energy of = + 590 kJ mol-1 and that of (C—C) = + 331 kJ mol-1 at 298 K.Enthalpy change for the polymerisation of ethene to polyethene is (where n is large integral value)a)72 kJ mol-1b)-72 kJ mol-1c)279 kJ mol-1d)-279 kJ mol-1Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Bond dissociation energy of = + 590 kJ mol-1 and that of (C—C) = + 331 kJ mol-1 at 298 K.Enthalpy change for the polymerisation of ethene to polyethene is (where n is large integral value)a)72 kJ mol-1b)-72 kJ mol-1c)279 kJ mol-1d)-279 kJ mol-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bond dissociation energy of = + 590 kJ mol-1 and that of (C—C) = + 331 kJ mol-1 at 298 K.Enthalpy change for the polymerisation of ethene to polyethene is (where n is large integral value)a)72 kJ mol-1b)-72 kJ mol-1c)279 kJ mol-1d)-279 kJ mol-1Correct answer is option 'B'. Can you explain this answer?.
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