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If x1, x2 and x3 are enthalpies of H - H, O = O and O - H bonds respectively, and x4 is the enthalpy of vaporisation of water, estimate the standard enthalpy of combustion of hydrogen
- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
If x1, x2and x3are enthalpies of H - H, O = O and O - H bonds respecti...
Combustion of hydrogen:
H2 + ½ O2→H2O (H−O−H)
As water contains two O−H bonds.
So, combustion enthalpy of hydrogen is:
ΔH= Bond energy of reactant − Bond energy of the product − Enthalpy of vaporization.
ΔH=x1+22−2x3−x4
H2 + ½ O2→H2O (H−O−H)
As water contains two O−H bonds.
So, combustion enthalpy of hydrogen is:
ΔH= Bond energy of reactant − Bond energy of the product − Enthalpy of vaporization.
ΔH=x1+22−2x3−x4
Most Upvoted Answer
If x1, x2and x3are enthalpies of H - H, O = O and O - H bonds respecti...
Combustion of hydrogen:
H2 + ½ O2→H2O (H−O−H)
As water contains two O−H bonds.
So, combustion enthalpy of hydrogen is:
ΔH= Bond energy of reactant − Bond energy of the product − Enthalpy of vaporization.
ΔH=x1+22−2x3−x4
H2 + ½ O2→H2O (H−O−H)
As water contains two O−H bonds.
So, combustion enthalpy of hydrogen is:
ΔH= Bond energy of reactant − Bond energy of the product − Enthalpy of vaporization.
ΔH=x1+22−2x3−x4
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Community Answer
If x1, x2and x3are enthalpies of H - H, O = O and O - H bonds respecti...
Option B is correct answer
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