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(i) Cis - 2 - butene → trans - 2 - butene, ΔH1
(ii) Cis - 2 - butene → 1 - butene, ΔH2
(iii) Trans - 2 - butene is more stable than cis - 2 - butene.
(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol
(v) 9ΔH1 + 5 ΔH2 = 0
(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/mol
The value of ΔH1 & ΔH2 in Kcal/mole are
- a)-1.0, 1.8
- b)1.8, -1.0
- c)-5,9
- d)-2, 3, 6
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
(i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 -...
Trans-2-butene + 6O2(g) → 4CO2(g) + 4H2O(l)
∆H = -647.0 kcal/mol ---(I)
1 - butene + 6O2(g) → 4CO2(g) + 4H2O(l)
ΔH = -649.8 kcal/mol ---(II)
On (I)-(II)
Trans-2-butene → 1 - butene
ΔH = 2.7 kcal/mol
ΔH = (Hf)1-Butene - (Hf)trans-2-butene
= H2 - H1
H2 - H1 = 2.7 -----(A)
And 9ΔH1 + 5ΔH2 = 0 -----(B)
On solving eqn (A) and (B), we get
H1 = -1.0 and H2 = 1.8
∆H = -647.0 kcal/mol ---(I)
1 - butene + 6O2(g) → 4CO2(g) + 4H2O(l)
ΔH = -649.8 kcal/mol ---(II)
On (I)-(II)
Trans-2-butene → 1 - butene
ΔH = 2.7 kcal/mol
ΔH = (Hf)1-Butene - (Hf)trans-2-butene
= H2 - H1
H2 - H1 = 2.7 -----(A)
And 9ΔH1 + 5ΔH2 = 0 -----(B)
On solving eqn (A) and (B), we get
H1 = -1.0 and H2 = 1.8
Most Upvoted Answer
(i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 -...
Cis-2-butene is an organic compound with the chemical formula C4H8. It is an alkene, meaning it contains a carbon-carbon double bond. The "cis" prefix indicates that the two methyl groups attached to the double bond are on the same side of the molecule.
The structure of cis-2-butene can be represented as follows:
CH3CH=CHCH3
In this structure, the double bond is between the second and third carbon atoms, and the two methyl groups are on the same side of the double bond.
The structure of cis-2-butene can be represented as follows:
CH3CH=CHCH3
In this structure, the double bond is between the second and third carbon atoms, and the two methyl groups are on the same side of the double bond.
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(i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 -...
A
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(i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer?
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(i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer?.
(i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer?.
Solutions for (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
(i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer?, a detailed solution for (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice (i) Cis - 2 - butene →trans - 2 - butene, ΔH1(ii) Cis - 2 - butene →1 - butene, ΔH2(iii) Trans - 2 - butene is more stable than cis - 2 - butene.(iv) Enthalpy of combustion of 1 - butene, ΔH = -649.8 kcal/mol(v) 9ΔH1+ 5 ΔH2= 0(vi) Enthalpy of combustion of trans 2 - butene, ΔH = -647.0 kcal/molThe value of ΔH1& ΔH2in Kcal/mole area)-1.0, 1.8b)1.8, -1.0c)-5,9d)-2, 3, 6Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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