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When 2,3-dibromobutane is treated with KOH in ethanol, 2-bromo-2-butene is formed which does not undergo further dehydrobromination to form 2-butyne under similar condition becausea)H and Br are not transb)there is no further B— H availablec)vinyl bromide are very less reactive in E2 elimination reactiond)reactant is more stable than productCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared
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When 2,3-dibromobutane is treated with KOH in ethanol, 2-bromo-2-butene is formed which does not undergo further dehydrobromination to form 2-butyne under similar condition becausea)H and Br are not transb)there is no further B— H availablec)vinyl bromide are very less reactive in E2 elimination reactiond)reactant is more stable than productCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for When 2,3-dibromobutane is treated with KOH in ethanol, 2-bromo-2-butene is formed which does not undergo further dehydrobromination to form 2-butyne under similar condition becausea)H and Br are not transb)there is no further B— H availablec)vinyl bromide are very less reactive in E2 elimination reactiond)reactant is more stable than productCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of When 2,3-dibromobutane is treated with KOH in ethanol, 2-bromo-2-butene is formed which does not undergo further dehydrobromination to form 2-butyne under similar condition becausea)H and Br are not transb)there is no further B— H availablec)vinyl bromide are very less reactive in E2 elimination reactiond)reactant is more stable than productCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice When 2,3-dibromobutane is treated with KOH in ethanol, 2-bromo-2-butene is formed which does not undergo further dehydrobromination to form 2-butyne under similar condition becausea)H and Br are not transb)there is no further B— H availablec)vinyl bromide are very less reactive in E2 elimination reactiond)reactant is more stable than productCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.