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The reaction CH4(g) + Cl2(g) → CH3Cl(g) + HCl(g) has ΔH = -25 kCal.
From the given data, what is the bond energy of Cl - Cl bond
  • a)
    70 kCal 
  • b)
    80 kCal
  • c)
     67.75 kCal
  • d)
     57.75 kCal
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The reaction CH4(g) + Cl2(g) →CH3Cl(g) + HCl(g) has ΔH = -2...
During bond breakage energy is absorbed and during bond formation it is released. From the reaction we can say that 1 C-H bond is broken 1 Cl-Cl bond is broken 1 c-cl bond is formed and 1 h-cl bond is formed. so using the sign conventions the equation becomes
x+y-84-103= -25 (∆H = -25)
5x=9y ..putting x=9/5y we get y = 57.75 kCal
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Most Upvoted Answer
The reaction CH4(g) + Cl2(g) →CH3Cl(g) + HCl(g) has ΔH = -2...
During bond breakage energy is absorbed and during bond formation it is released. From the reaction we can say that 1 C-H bond is broken 1 Cl-Cl bond is broken 1 c-cl bond is formed and 1 h-cl bond is formed. so using the sign conventions the equation becomes
x+y-84-103= -25 (∆H = -25)
5x=9y ..putting x=9/5y we get y = 57.75 kCal
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Community Answer
The reaction CH4(g) + Cl2(g) →CH3Cl(g) + HCl(g) has ΔH = -2...
During bond breakage energy is absorbed and during bond formation it is released. From the reaction we can say that 1 c-h bond is broken 1 cl-cl bond is broken 1 c-cl bond is formed and 1 h-cl bond is formed. so using the sign conventions the equation becomes
x+y-84-103= -25 (∆H=-25)
5x=9y ..putting x=9/5y we get y = 57.75 kCal
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