A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and...
Let heat evolved in the 1st case is Q1 and that in the 2nd case is Q2. Then Q2 = 1/2Q1
However, Q1 = 1000T1 and Q2 = 500T2
Therefore, 500T2 = ½ 1000T1 i.e. T1 = T2
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A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and...
A solution of 500 ml of 0.2 M KOH and 500 ml of 0.2 M HCl is mixed and...
Explanation:
When the solution of KOH and HCl is mixed, a neutralization reaction occurs. The reaction between KOH and HCl can be represented as follows:
KOH + HCl → KCl + H2O
The reaction is exothermic, which means it releases heat energy. The rise in temperature observed during the mixing of the solutions is an indication of this heat energy release.
Now let's analyze the given options to determine the relationship between T1 and T2.
a) T1 = T2:
If option a is true, it means that the rise in temperature is the same regardless of the volumes of the solutions used. This would suggest that the heat energy released during the reaction is independent of the amount of reactants used. However, this is not necessarily true. The heat energy released during a reaction is directly proportional to the amount of reactants involved.
b) T1 = 2T2:
If option b is true, it means that the rise in temperature is doubled when the volumes of the solutions are halved. This is not expected as the heat energy released during a reaction is proportional to the amount of reactants involved. Therefore, option b is not true.
c) T1 = 4T2:
If option c is true, it means that the rise in temperature is quadrupled when the volumes of the solutions are halved. Again, this is not expected as the heat energy released during a reaction is proportional to the amount of reactants involved. Therefore, option c is not true.
d) T2 = 9T1:
If option d is true, it means that the rise in temperature is nine times greater when the volumes of the solutions are halved. This is also not expected as the heat energy released during a reaction is proportional to the amount of reactants involved. Therefore, option d is not true.
Therefore, the correct answer is option a: T1 = T2. This means that the rise in temperature observed when the volumes of the solutions are halved is the same as the rise in temperature observed when the volumes are doubled.