Class 11 Exam > Class 11 Questions > When 1 mole of an ideal gas at 20 atm pressur...
Start Learning for Free
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)
- a)80.2 J.k-lmo1-1
- b)62.42 kJ.k-1 mol-1
- c)120 x 102 J1c1mol-1
- d)27.22 J.k-1mor
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands...
Most Upvoted Answer
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands...
Entropy Change Calculation
- Given initial pressure (P1) = 20 atm
- Given initial volume (V1) = 15 L
- Given final pressure (P2) = 10 atm
- Given final volume (V2) = 60 L
- Given heat capacity at constant pressure (Cp) = 30.96 J mol-1 K-1
Entropy Change Formula
The entropy change (ΔS) for an ideal gas undergoing an isothermal reversible process can be calculated using the formula:
ΔS = nR ln(V2/V1)
where n is the number of moles of the gas and R is the gas constant.
Calculate Entropy Change
Given that 1 mole of gas is present:
ΔS = (1 mol) * (8.314 J mol-1 K-1) * ln(60/15)
ΔS = 1 * 8.314 * ln(4)
ΔS = 1 * 8.314 * 1.386
ΔS = 11.51 J K-1
Since the given options are in kJ/mol, we convert the result to kJ/mol:
ΔS = 11.51 J K-1 = 0.01151 kJ K-1 = 27.22 J K-1 mol-1
Therefore, the correct answer is option 'D' - 27.22 J K-1 mol-1.
- Given initial pressure (P1) = 20 atm
- Given initial volume (V1) = 15 L
- Given final pressure (P2) = 10 atm
- Given final volume (V2) = 60 L
- Given heat capacity at constant pressure (Cp) = 30.96 J mol-1 K-1
Entropy Change Formula
The entropy change (ΔS) for an ideal gas undergoing an isothermal reversible process can be calculated using the formula:
ΔS = nR ln(V2/V1)
where n is the number of moles of the gas and R is the gas constant.
Calculate Entropy Change
Given that 1 mole of gas is present:
ΔS = (1 mol) * (8.314 J mol-1 K-1) * ln(60/15)
ΔS = 1 * 8.314 * ln(4)
ΔS = 1 * 8.314 * 1.386
ΔS = 11.51 J K-1
Since the given options are in kJ/mol, we convert the result to kJ/mol:
ΔS = 11.51 J K-1 = 0.01151 kJ K-1 = 27.22 J K-1 mol-1
Therefore, the correct answer is option 'D' - 27.22 J K-1 mol-1.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer?
Question Description
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer?.
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer?.
Solutions for When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice When 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume become 60 L. Calculate entropy change for the process (Cpm = 30.96 J mole-1 K-1)a)80.2 J.k-lmo1-1b)62.42 kJ.k-1 mol-1c)120 x 102 J1c1mol-1d)27.22 J.k-1morCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup