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A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force.
Verified Answer
A force acts for 10 sec on a stationary body of mass 100 kg after whi...
Given, m = 100 kg
Let F be the force that acts for t = 10 s
So, a = F/m ....(1)
Using Ist eq. of motion :
v = u + at
v = 10 a ..(2) [ considering the body starts from rest]
After 10s, the force ceases and the body moves with velocity v. In 5 sec, it covers a distance of 100 m.
As, Distance = Speed X time
so, 100 = (10 a) X 5
or a = 2 m/s^2 ..(3)
Putting this value of 'a' from eq. 3 into eq. 1, we get :
F = m a = 100 kg X 2 m/s^2 = 200 N
Putting value of 'a' from eq. 3 into eq. 2, we get :
v = 10 a = 10 s X 2 m/s^2 = 20 m/s
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Most Upvoted Answer
A force acts for 10 sec on a stationary body of mass 100 kg after whi...
Velocity acquired by the body:
To determine the velocity acquired by the body, we need to analyze the motion of the body during the two different time intervals.
- In the first 10 seconds, a force acts on the stationary body. Since the body is initially at rest, the force results in an acceleration. We can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). Rearranging the equation, we have acceleration (a) = force (F) / mass (m).
Given that the mass of the body is 100 kg, we can find the acceleration produced by the force. However, to determine the velocity acquired during this time interval, we also need to know the initial velocity (which is zero in this case). Therefore, we can use the equation of motion: final velocity (v) = initial velocity (u) + acceleration (a) * time (t).
- In the next 5 seconds, the force ceases to act, and the body continues to move due to its acquired velocity. Since no external force is acting on the body, it will move with a constant velocity. The distance covered during this time interval can be calculated using the equation of motion: distance (s) = initial velocity (u) * time (t) + 0.5 * acceleration (a) * time (t)^2. In this case, the initial velocity is the final velocity acquired during the previous time interval.
Acceleration produced by the force:
To find the acceleration produced by the force, we can use the equation a = F / m, where a is the acceleration, F is the force, and m is the mass of the body. Substituting the known values (mass = 100 kg), we can calculate the acceleration.
Magnitude of the force:
To determine the magnitude of the force, we need to consider the motion of the body during the first time interval when the force is acting. We can use the equation F = m * a, where F is the force, m is the mass of the body, and a is the acceleration. By substituting the known values (mass = 100 kg, acceleration calculated earlier), we can calculate the magnitude of the force.
In conclusion, to find the velocity acquired by the body, we need to calculate the acceleration produced by the force using a = F / m. Then, using the equations of motion, we can determine the velocity acquired during the first time interval and the distance covered during the second time interval. The acceleration produced by the force can be found using the equation a = F / m, and the magnitude of the force can be calculated using F = m * a.
To determine the velocity acquired by the body, we need to analyze the motion of the body during the two different time intervals.
- In the first 10 seconds, a force acts on the stationary body. Since the body is initially at rest, the force results in an acceleration. We can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). Rearranging the equation, we have acceleration (a) = force (F) / mass (m).
Given that the mass of the body is 100 kg, we can find the acceleration produced by the force. However, to determine the velocity acquired during this time interval, we also need to know the initial velocity (which is zero in this case). Therefore, we can use the equation of motion: final velocity (v) = initial velocity (u) + acceleration (a) * time (t).
- In the next 5 seconds, the force ceases to act, and the body continues to move due to its acquired velocity. Since no external force is acting on the body, it will move with a constant velocity. The distance covered during this time interval can be calculated using the equation of motion: distance (s) = initial velocity (u) * time (t) + 0.5 * acceleration (a) * time (t)^2. In this case, the initial velocity is the final velocity acquired during the previous time interval.
Acceleration produced by the force:
To find the acceleration produced by the force, we can use the equation a = F / m, where a is the acceleration, F is the force, and m is the mass of the body. Substituting the known values (mass = 100 kg), we can calculate the acceleration.
Magnitude of the force:
To determine the magnitude of the force, we need to consider the motion of the body during the first time interval when the force is acting. We can use the equation F = m * a, where F is the force, m is the mass of the body, and a is the acceleration. By substituting the known values (mass = 100 kg, acceleration calculated earlier), we can calculate the magnitude of the force.
In conclusion, to find the velocity acquired by the body, we need to calculate the acceleration produced by the force using a = F / m. Then, using the equations of motion, we can determine the velocity acquired during the first time interval and the distance covered during the second time interval. The acceleration produced by the force can be found using the equation a = F / m, and the magnitude of the force can be calculated using F = m * a.
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A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force.
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A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force. for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force. covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force..
A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force. for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force. covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force acts for 10 sec on a stationary body of mass 100 kg after which the force seizes to act.The body moves through a distance of 100 m in the next 5 sec.Find-the velocity acquired by the body,the acceleration produced by the force,the magnitude of the force..
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