Chemistry Exam > Chemistry Questions > A graph is plotted between log10K and 1/T in ...
Start Learning for Free
A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy?
- a)2 cal
- b)1 cal
- c)4 cal
- d)0.5 cal
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A graph is plotted between log10K and 1/T in which straight line BC ha...
Log K = log A-Ea/(2.303RT) so -Ea/(2.303R)is slop is equal to -1/2.303
Ea/R=1 (2.303 cancel out)
Ea= 2 cal (R in cal/KMol)
Ea= 2 cal (R in cal/KMol)
Free Test
FREE
| Start Free Test |
Community Answer
A graph is plotted between log10K and 1/T in which straight line BC ha...
To determine the activation energy from the given information, we need to understand the relationship between the variables involved and the equations that describe this relationship.
The equation that relates the rate constant (K) of a reaction to temperature (T) is called the Arrhenius equation:
K = Ae^(-Ea/RT)
where:
- K is the rate constant
- A is the pre-exponential factor or frequency factor
- Ea is the activation energy
- R is the gas constant
- T is the temperature in Kelvin
In order to simplify the equation and make it more suitable for graphical analysis, we can take the logarithm (base 10) of both sides:
log10K = log10A - (Ea/2.303RT)
From the given information, we know that a straight line BC has no slope and that tan() is equal to -1/2.303. This tells us that the slope of the line is -1/2.303.
The slope of a straight line in a graph represents the coefficient of the variable on the x-axis. In this case, the x-axis represents 1/T, so the coefficient of 1/T is equal to -1/2.303.
We can rewrite the equation in terms of the slope:
-1/2.303 = -Ea/2.303R
Simplifying the equation further:
Ea = R
Since the value of R is approximately 2 cal, the activation energy (Ea) is also approximately 2 cal.
Therefore, the correct answer is option A) 2 cal.
The equation that relates the rate constant (K) of a reaction to temperature (T) is called the Arrhenius equation:
K = Ae^(-Ea/RT)
where:
- K is the rate constant
- A is the pre-exponential factor or frequency factor
- Ea is the activation energy
- R is the gas constant
- T is the temperature in Kelvin
In order to simplify the equation and make it more suitable for graphical analysis, we can take the logarithm (base 10) of both sides:
log10K = log10A - (Ea/2.303RT)
From the given information, we know that a straight line BC has no slope and that tan() is equal to -1/2.303. This tells us that the slope of the line is -1/2.303.
The slope of a straight line in a graph represents the coefficient of the variable on the x-axis. In this case, the x-axis represents 1/T, so the coefficient of 1/T is equal to -1/2.303.
We can rewrite the equation in terms of the slope:
-1/2.303 = -Ea/2.303R
Simplifying the equation further:
Ea = R
Since the value of R is approximately 2 cal, the activation energy (Ea) is also approximately 2 cal.
Therefore, the correct answer is option A) 2 cal.
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer?
Question Description
A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer?.
A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A graph is plotted between log10K and 1/T in which straight line BC has no slope and tan(ᴓ) = -1/2.303 and intercept on y-axis is 5. What is activation energy? a)2 cal b)1 cal c)4 cal d)0.5 calCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup