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A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient?
Verified Answer
A potentiometre wore has a resistance 40 ohm and it's length 10m. it ...
Given in the question :-
Refer to the attachment
Wire resistance = 40 ohm
length = 10 m.
R = 760 ohm
v = 2
We know the formula ,
i = v/R
i = 2/(760 +40)
i = 2/800 A
i = 1/400 A .
Now, Potential drop at wire = i x 40
= 1/10 v.
Potential gradient = Potential drop / length
Potential gradient = (1/10) / 10 v/m
Potential gradient = 0.01 v/m.
Refer to the attachment
Wire resistance = 40 ohm
length = 10 m.
R = 760 ohm
v = 2
We know the formula ,
i = v/R
i = 2/(760 +40)
i = 2/800 A
i = 1/400 A .
Now, Potential drop at wire = i x 40
= 1/10 v.
Potential gradient = Potential drop / length
Potential gradient = (1/10) / 10 v/m
Potential gradient = 0.01 v/m.
This question is part of UPSC exam. View all Class 12 courses
Most Upvoted Answer
A potentiometre wore has a resistance 40 ohm and it's length 10m. it ...
Given:
Resistance of potentiometer wire (R) = 40 ohm
Length of potentiometer wire (L) = 10m
Resistance in series (r) = 760 ohm
EMF of the battery (E) = 2V
To Find:
Potential gradient (∆V/∆L)
Solution:
Step 1: Calculate the total resistance in the circuit.
Total resistance (Rt) = R + r
Step 2: Calculate the current flowing in the circuit using Ohm's law.
I = E/Rt
Step 3: Calculate the potential difference across the potentiometer wire using Ohm's law.
∆V = I * R
Step 4: Calculate the potential gradient (∆V/∆L).
Potential gradient (∆V/∆L) = ∆V / L
Step 1: Calculate the total resistance in the circuit.
Rt = R + r
= 40 + 760
= 800 ohm
Step 2: Calculate the current flowing in the circuit using Ohm's law.
I = E/Rt
= 2/800
= 0.0025 A
Step 3: Calculate the potential difference across the potentiometer wire using Ohm's law.
∆V = I * R
= 0.0025 * 40
= 0.1 V
Step 4: Calculate the potential gradient (∆V/∆L).
Potential gradient (∆V/∆L) = ∆V / L
= 0.1 / 10
= 0.01 V/m
Answer:
The potential gradient in the given circuit is 0.01 V/m.
Resistance of potentiometer wire (R) = 40 ohm
Length of potentiometer wire (L) = 10m
Resistance in series (r) = 760 ohm
EMF of the battery (E) = 2V
To Find:
Potential gradient (∆V/∆L)
Solution:
Step 1: Calculate the total resistance in the circuit.
Total resistance (Rt) = R + r
Step 2: Calculate the current flowing in the circuit using Ohm's law.
I = E/Rt
Step 3: Calculate the potential difference across the potentiometer wire using Ohm's law.
∆V = I * R
Step 4: Calculate the potential gradient (∆V/∆L).
Potential gradient (∆V/∆L) = ∆V / L
Step 1: Calculate the total resistance in the circuit.
Rt = R + r
= 40 + 760
= 800 ohm
Step 2: Calculate the current flowing in the circuit using Ohm's law.
I = E/Rt
= 2/800
= 0.0025 A
Step 3: Calculate the potential difference across the potentiometer wire using Ohm's law.
∆V = I * R
= 0.0025 * 40
= 0.1 V
Step 4: Calculate the potential gradient (∆V/∆L).
Potential gradient (∆V/∆L) = ∆V / L
= 0.1 / 10
= 0.01 V/m
Answer:
The potential gradient in the given circuit is 0.01 V/m.
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A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient?
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A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient? .
A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A potentiometre wore has a resistance 40 ohm and it's length 10m. it is connected to a resistance of 760ohm in series. If emf of battery is 2V then what will be potential gradient? .
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