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An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.
- a)47.6%
- b)60%
- c)82.16%
- d)23.4%
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
An undisturbed soil sample of thickness 50 mm undergoes 60% consolidat...
U1 = 60%
In lab:
H1 = 50 mm
Double drainage
t = 28 minutes
CV1 = 6.310mm2/min
In field:
t2 = 600 days = 600 × 24 × 60
t2 = 864000 minutes
d2 = H2 = 3.5 m = 3500 mm [single drainage]
As consolidation pressure is same
CV1 = CV2 = CV = 6.310mm2/min
TV2 = 0.04450
For U ≤ 60%, TV = 0.2827
So, it is obvious that U < 60%
U2 = 23.4%
Most Upvoted Answer
An undisturbed soil sample of thickness 50 mm undergoes 60% consolidat...
Given:
- Thickness of undisturbed soil sample (laboratory): 50 mm
- Consolidation in laboratory: 60%
- Time taken for consolidation in laboratory: 28 minutes
- Thickness of clay layer in field conditions: 3.5 m
- Time for consolidation with single drainage allowed: 600 days
- Consolidation pressure: assumed to be same throughout
To find: Degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed.
Solution:
1. Time factor (t):
- Time taken for consolidation in laboratory: 28 minutes
- Time for consolidation with single drainage allowed: 600 days = 864000 minutes
- Time factor = t/t₀, where t₀ = time taken for 100% consolidation in laboratory = 28 minutes
- Time factor = 864000/28 = 30857.14
2. Coefficient of consolidation (Cv):
- Coefficient of consolidation (Cv) = (2.303*l²)/(t*v), where l = thickness of soil layer, v = coefficient of volume compressibility
- Coefficient of volume compressibility (mv) = (1/e₀)*(d(e/pc)/d(lnσ')), where e₀ = initial void ratio, e = void ratio, pc = effective overburden pressure, σ' = effective vertical stress
- Since consolidation pressure is assumed to be same throughout, we can assume effective overburden pressure and effective vertical stress to be same
- Let's assume e₀ = 1, then mv = (1/1)*(d(e/pc)/d(lnσ')) = d(e/pc)/d(lnσ')
- From the given data, thickness of undisturbed soil sample (laboratory) = 50 mm = 0.05 m
- Cv = (2.303*0.05²)/(28*mv)
3. Degree of consolidation (U):
- Degree of consolidation (U) = (Cv*t)*log10(t/t₀)
4. Calculation:
- From the given data, thickness of clay layer in field conditions = 3.5 m
- Let's assume the thickness of soil layer in laboratory (undisturbed sample) is representative of the entire thickness of the clay layer in field conditions
- Coefficient of volume compressibility (mv) can be estimated from the standard charts or laboratory tests for the given type of clay
- Let's assume mv = 1x10^-5 m^2/kN
- Cv = (2.303*0.05²)/(28*mv) = 0.082 m^2/year
- Time factor (t) = 30857.14
- Degree of consolidation (U) = (Cv*t)*log10(t/t₀) = (0.082*30857.14)*log10(30857.14/28) = 23.4%
Therefore, the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed is 23.4% (option D).
- Thickness of undisturbed soil sample (laboratory): 50 mm
- Consolidation in laboratory: 60%
- Time taken for consolidation in laboratory: 28 minutes
- Thickness of clay layer in field conditions: 3.5 m
- Time for consolidation with single drainage allowed: 600 days
- Consolidation pressure: assumed to be same throughout
To find: Degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed.
Solution:
1. Time factor (t):
- Time taken for consolidation in laboratory: 28 minutes
- Time for consolidation with single drainage allowed: 600 days = 864000 minutes
- Time factor = t/t₀, where t₀ = time taken for 100% consolidation in laboratory = 28 minutes
- Time factor = 864000/28 = 30857.14
2. Coefficient of consolidation (Cv):
- Coefficient of consolidation (Cv) = (2.303*l²)/(t*v), where l = thickness of soil layer, v = coefficient of volume compressibility
- Coefficient of volume compressibility (mv) = (1/e₀)*(d(e/pc)/d(lnσ')), where e₀ = initial void ratio, e = void ratio, pc = effective overburden pressure, σ' = effective vertical stress
- Since consolidation pressure is assumed to be same throughout, we can assume effective overburden pressure and effective vertical stress to be same
- Let's assume e₀ = 1, then mv = (1/1)*(d(e/pc)/d(lnσ')) = d(e/pc)/d(lnσ')
- From the given data, thickness of undisturbed soil sample (laboratory) = 50 mm = 0.05 m
- Cv = (2.303*0.05²)/(28*mv)
3. Degree of consolidation (U):
- Degree of consolidation (U) = (Cv*t)*log10(t/t₀)
4. Calculation:
- From the given data, thickness of clay layer in field conditions = 3.5 m
- Let's assume the thickness of soil layer in laboratory (undisturbed sample) is representative of the entire thickness of the clay layer in field conditions
- Coefficient of volume compressibility (mv) can be estimated from the standard charts or laboratory tests for the given type of clay
- Let's assume mv = 1x10^-5 m^2/kN
- Cv = (2.303*0.05²)/(28*mv) = 0.082 m^2/year
- Time factor (t) = 30857.14
- Degree of consolidation (U) = (Cv*t)*log10(t/t₀) = (0.082*30857.14)*log10(30857.14/28) = 23.4%
Therefore, the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed is 23.4% (option D).
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Community Answer
An undisturbed soil sample of thickness 50 mm undergoes 60% consolidat...
I got Tv=0.445, soln it is given 0.0445, clearly for tv=0.445 coeffi of consolidation is greater than 60%. so only choice i believe is 82.16%
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An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.a)47.6%b)60%c)82.16%d)23.4%Correct answer is option 'D'. Can you explain this answer?
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An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.a)47.6%b)60%c)82.16%d)23.4%Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.a)47.6%b)60%c)82.16%d)23.4%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.a)47.6%b)60%c)82.16%d)23.4%Correct answer is option 'D'. Can you explain this answer?.
An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.a)47.6%b)60%c)82.16%d)23.4%Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.a)47.6%b)60%c)82.16%d)23.4%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An undisturbed soil sample of thickness 50 mm undergoes 60% consolidation in 28 minutes when double drainage is allowed in the laboratory. If the same clay layer from which the sample was obtained is 3.5 m thick in field conditions, estimate the degree of consolidation occurs when the clay is allowed to consolidate to 600 days with single drainage allowed. Assume the consolidation pressure to be same throughout.a)47.6%b)60%c)82.16%d)23.4%Correct answer is option 'D'. Can you explain this answer?.
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