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When in a saturated solution of NaCl, HCl is passed, pure precipitate of NaCl is formed. This is due to the fact:
- a)That solubility of NaCl decreases
- b)That HCl is strong acid
- c)That the ionic product of NaCl exceeds the solubility product of NaCl.
- d)That HCl is highly soluble in water
Correct answer is option 'C'. Can you explain this answer?
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When in a saturated solution of NaCl, HCl is passed, pure precipitate ...
In saturated solution of NaCl,equillibrium is established between ions and unionised NaCl. When HCl gas is passed through saturated solution of NaCl,it is completely dissociated to form H+ and Cl- ions. Cl- ion is common to both electrolyte ,hence Cl- ion concentration in solution increases.
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When in a saturated solution of NaCl, HCl is passed, pure precipitate ...
Explanation:
When HCl is passed through a saturated solution of NaCl, a pure precipitate of NaCl is formed. This phenomenon can be explained by the following reasons:
1. Solubility of NaCl decreases:
When HCl is added to a saturated solution of NaCl, the chloride ions (Cl-) from HCl combine with the sodium ions (Na+) present in the solution to form NaCl. This reaction reduces the concentration of Na+ ions in the solution, which in turn decreases the solubility of NaCl. As a result, NaCl precipitates out of the solution.
2. Ionic product exceeds solubility product:
The solubility product (Ksp) of NaCl represents the maximum amount of NaCl that can be dissolved in a given solvent. When HCl is added to the saturated solution, the concentration of Na+ ions decreases, while the concentration of Cl- ions increases. This increase in the concentration of Cl- ions exceeds the solubility product of NaCl, leading to the precipitation of pure NaCl.
3. HCl is a strong acid:
HCl is a strong acid, meaning it ionizes completely in water to release H+ ions. The presence of H+ ions in the solution can react with the Na+ ions to form NaCl. This reaction further reduces the concentration of Na+ ions, promoting the precipitation of NaCl.
4. HCl solubility in water:
HCl is highly soluble in water, which means it readily dissolves and dissociates into H+ and Cl- ions. The high solubility of HCl allows for a high concentration of Cl- ions to be present in the solution, facilitating the formation of NaCl precipitate.
In conclusion, the formation of a pure precipitate of NaCl when HCl is passed through a saturated solution of NaCl is due to the decrease in solubility of NaCl, the excess of the ionic product over the solubility product, the strong acid nature of HCl, and the high solubility of HCl in water.
When HCl is passed through a saturated solution of NaCl, a pure precipitate of NaCl is formed. This phenomenon can be explained by the following reasons:
1. Solubility of NaCl decreases:
When HCl is added to a saturated solution of NaCl, the chloride ions (Cl-) from HCl combine with the sodium ions (Na+) present in the solution to form NaCl. This reaction reduces the concentration of Na+ ions in the solution, which in turn decreases the solubility of NaCl. As a result, NaCl precipitates out of the solution.
2. Ionic product exceeds solubility product:
The solubility product (Ksp) of NaCl represents the maximum amount of NaCl that can be dissolved in a given solvent. When HCl is added to the saturated solution, the concentration of Na+ ions decreases, while the concentration of Cl- ions increases. This increase in the concentration of Cl- ions exceeds the solubility product of NaCl, leading to the precipitation of pure NaCl.
3. HCl is a strong acid:
HCl is a strong acid, meaning it ionizes completely in water to release H+ ions. The presence of H+ ions in the solution can react with the Na+ ions to form NaCl. This reaction further reduces the concentration of Na+ ions, promoting the precipitation of NaCl.
4. HCl solubility in water:
HCl is highly soluble in water, which means it readily dissolves and dissociates into H+ and Cl- ions. The high solubility of HCl allows for a high concentration of Cl- ions to be present in the solution, facilitating the formation of NaCl precipitate.
In conclusion, the formation of a pure precipitate of NaCl when HCl is passed through a saturated solution of NaCl is due to the decrease in solubility of NaCl, the excess of the ionic product over the solubility product, the strong acid nature of HCl, and the high solubility of HCl in water.
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When in a saturated solution of NaCl, HCl is passed, pure precipitate of NaCl is formed. This is due to the fact:a)That solubility of NaCl decreasesb)That HCl is strong acidc)That the ionic product of NaCl exceeds the solubility product of NaCl.d)That HCl is highly soluble in waterCorrect answer is option 'C'. Can you explain this answer?
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