Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; andDelta;H= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer?

EduRev

All Courses

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

Class 11 Exam > Class 11 Questions > Densities of diamond and graphite are 3.5 and...

Join the Discussion on the App

Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for

C(diamond)

C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are

a)
High pressure and low temperature
b)
Low pressure and high temperature
c)
High pressure and high temperature
d)
Low pressure and low temperature

Correct answer is option 'C'. Can you explain this answer?

FREE This question is part of

R.C. Mukherjee Test: Chemical Equilibrium

Attempt Test

Attempt this Test

Verified Answer

Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively ...

It is exothermic reaction so it favours low temperature density of graphite is less than diamondlow pessure.

⇒ but for formation of diamond Reverse condition high temperature & high pressure.

View all questions of this test

View all answers Start learning for free

< Previous Question Next Question >

Explore Courses for Class 11 exam

Similar Class 11 Doubts

Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamon d) C (graphit e) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are

View answer

In a two-step exothermic reactionSteps 1 and 2 are favoured respectively by [1997]

View answer

Importance of high specific heat capacity of water for life Specific heat capacity of a substance is the amount of heat required to raise the temperature of that substance by 1 K. It is expressed in the units J/ (kg K). A high specific heat of a substance means that a large amount of heat is required to raise the temperature of the substance. Water has the highest known specific heat capacity. Its specific heat capacity is 4.186 K J/ (kg K) i.e. to raise the temperature of 1 kg of water by 1 Kelvin it requires 4.186 KJ of heat. For comparison sake, Copper requires only 385 Joules of heat to raise 1 kilogram of copper by 1 Kelvin. It also interesting to know that the specific heat capacities in two other phases of water (i.e. ice and water vapour) are less than this. High specific heat of water is mainly due to the presence of a large number of hydrogen bonds between molecules of water. On a beach on a sunny day, it is noticed that the sand is often quite hot to walk on, but the water is always cool, even in the shallows. This is because sand has a lower specific heat capacity than that of water. Sand takes less energy to raise the temperature by one degree. Because water has a high specific heat capacity, it requires more energy to raise the temperature by one degree. Since the sun puts same rate of energy on water and sand, which heats up sand more quickly and water more slowly. Water covers around 70% of the Earth's surface and its high specific heat plays a very important role to sustain life in the earth. It is able to absorb a lot of heat without a significant rise in the temperature. When temperatures decrease, the heat which is stored is released, restraining a rapid drop in temperature. The combined effect is the buffering of heat. A relatively constant temperature without sudden rise and drop is essential to sustain life. Hence water is important for life.Q. To raise the temperature of 1 kg of water and 1 kg of copper by 1 Kelvin, 4.186 KJ and 385 Joule of heat are required respectively. Which one will get heated up faster if exposed to sun?

View answer

Importance of high specific heat capacity of water for life Specific heat capacity of a substance is the amount of heat required to raise the temperature of that substance by 1 K. It is expressed in the units J/ (kg K). A high specific heat of a substance means that a large amount of heat is required to raise the temperature of the substance. Water has the highest known specific heat capacity. Its specific heat capacity is 4.186 K J/ (kg K) i.e. to raise the temperature of 1 kg of water by 1 Kelvin it requires 4.186 KJ of heat. For comparison sake, Copper requires only 385 Joules of heat to raise 1 kilogram of copper by 1 Kelvin. It also interesting to know that the specific heat capacities in two other phases of water (i.e. ice and water vapour) are less than this. High specific heat of water is mainly due to the presence of a large number of hydrogen bonds between molecules of water. On a beach on a sunny day, it is noticed that the sand is often quite hot to walk on, but the water is always cool, even in the shallows. This is because sand has a lower specific heat capacity than that of water. Sand takes less energy to raise the temperature by one degree. Because water has a high specific heat capacity, it requires more energy to raise the temperature by one degree. Since the sun puts same rate of energy on water and sand, which heats up sand more quickly and water more slowly. Water covers around 70% of the Earth's surface and its high specific heat plays a very important role to sustain life in the earth. It is able to absorb a lot of heat without a significant rise in the temperature. When temperatures decrease, the heat which is stored is released, restraining a rapid drop in temperature. The combined effect is the buffering of heat. A relatively constant temperature without sudden rise and drop is essential to sustain life. Hence water is important for life.Q. Which statement is false?

View answer

Importance of high specific heat capacity of water for life Specific heat capacity of a substance is the amount of heat required to raise the temperature of that substance by 1 K. It is expressed in the units J/ (kg K). A high specific heat of a substance means that a large amount of heat is required to raise the temperature of the substance. Water has the highest known specific heat capacity. Its specific heat capacity is 4.186 K J/ (kg K) i.e. to raise the temperature of 1 kg of water by 1 Kelvin it requires 4.186 KJ of heat. For comparison sake, Copper requires only 385 Joules of heat to raise 1 kilogram of copper by 1 Kelvin. It also interesting to know that the specific heat capacities in two other phases of water (i.e. ice and water vapour) are less than this. High specific heat of water is mainly due to the presence of a large number of hydrogen bonds between molecules of water. On a beach on a sunny day, it is noticed that the sand is often quite hot to walk on, but the water is always cool, even in the shallows. This is because sand has a lower specific heat capacity than that of water. Sand takes less energy to raise the temperature by one degree. Because water has a high specific heat capacity, it requires more energy to raise the temperature by one degree. Since the sun puts same rate of energy on water and sand, which heats up sand more quickly and water more slowly. Water covers around 70% of the Earth's surface and its high specific heat plays a very important role to sustain life in the earth. It is able to absorb a lot of heat without a significant rise in the temperature. When temperatures decrease, the heat which is stored is released, restraining a rapid drop in temperature. The combined effect is the buffering of heat. A relatively constant temperature without sudden rise and drop is essential to sustain life. Hence water is important for life.Q. Specific heat capacity of water is

View answer

Top Courses for Class 11View all

Chemistry Practice Tests: CUET Preparation

CUET Mock Test: Humanities Subjects 2025

Top Courses for Class 11

View all

Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer?

Share with a Friend

Answer this doubt

Question Description
Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer?.

Solutions for Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and forC(diamond)C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond area)High pressure and low temperatureb)Low pressure and high temperaturec)High pressure and high temperatured)Low pressure and low temperatureCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.

Explore Courses for Class 11 exam