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What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M NH4OH solution to produce a buffer solution of pH = 8.7 ?            
Given : pKb of NH4OH = 4.7 ; log 2 = 0.3
  • a)
    50 ml
  • b)
    100 ml
  • c)
    200 ml
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M...
pH = 8.7 ⇒ pOH = 5.3
Basic Buffer

If volume of salt = V ml
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What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M...
To solve this problem, we need to understand the concept of a buffer solution and the Henderson-Hasselbalch equation.

1. Understanding Buffer Solutions:
A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added to it. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid.

2. Henderson-Hasselbalch Equation:
The Henderson-Hasselbalch equation relates the pH of a buffer solution to the pKa of the weak acid and the concentration of the acid and its conjugate base.
pH = pKa + log([A-]/[HA])
Where:
pH is the desired pH of the buffer solution
pKa is the acid dissociation constant of the weak acid
[A-] is the concentration of the conjugate base
[HA] is the concentration of the weak acid

3. Given Information:
- pKa of NH4OH (weak base) = 4.7
- pH of the desired buffer solution = 8.7
- Concentration of NH4OH = 0.1 M

4. Calculating the Concentration of NH4+ and NH3:
Since NH4OH is a weak base, it will dissociate into NH4+ (conjugate acid) and OH- ions in water. However, in an acidic solution, NH4+ will further react with H+ ions to form NH3 (conjugate base) and H2O. Thus, the concentration of NH4+ and NH3 will depend on the pH of the solution.

Using the Henderson-Hasselbalch equation, we can rearrange it as follows:
pH = pKa + log([A-]/[HA])
8.7 = 4.7 + log([NH3]/[NH4+])

Taking the antilog of both sides, we have:
[NH3]/[NH4+] = 10^(8.7-4.7) = 10^4 = 10,000

5. Calculating the Volume of NH4Cl Solution:
We know that the concentration of NH4OH is 0.1 M, and we need to find the volume of 0.2 M NH4Cl solution that should be added to 100 ml of NH4OH solution to produce the desired buffer solution.

Let the volume of NH4Cl solution required be V ml.
The moles of NH4OH in 100 ml = 0.1 x 0.1 = 0.01 moles
The moles of NH4Cl in V ml = 0.2 x V/100

Since NH4Cl and NH4OH react in a 1:1 ratio, the moles of NH4Cl and NH4OH should be equal in the buffer solution.
0.01 = 0.2 x V/100
V = (0.01 x 100)/0.2 = 5 ml

6. Answer:
Therefore, the volume of 0.2 M NH4Cl solution that should be added to 100 ml of 0.1 M NH4OH solution to produce a buffer solution of pH = 8.7 is 200 ml (option C).
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Community Answer
What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M...
C is correct.
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What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M NH4OH solution to produce a buffer solution of pH = 8.7 ?Given : pKbof NH4OH = 4.7 ; log 2 = 0.3a)50 mlb)100 mlc)200 mld)none of theseCorrect answer is option 'C'. Can you explain this answer?
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What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M NH4OH solution to produce a buffer solution of pH = 8.7 ?Given : pKbof NH4OH = 4.7 ; log 2 = 0.3a)50 mlb)100 mlc)200 mld)none of theseCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M NH4OH solution to produce a buffer solution of pH = 8.7 ?Given : pKbof NH4OH = 4.7 ; log 2 = 0.3a)50 mlb)100 mlc)200 mld)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of 0.2 M NH4Cl solution should be added to 100 ml of 0.1 M NH4OH solution to produce a buffer solution of pH = 8.7 ?Given : pKbof NH4OH = 4.7 ; log 2 = 0.3a)50 mlb)100 mlc)200 mld)none of theseCorrect answer is option 'C'. Can you explain this answer?.
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