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The pKa of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA in which 50% of the acid is ionized is:
  • a)
    4.5
  • b)
    2.5
  • c)
    9.5
  • d)
    7.0
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The pKaof a weak acid (HA) is 4.5. The pOH of an aqueous buffered solu...

50% ionised ⇒ [Salt] = [Acid]
⇒ pH = pKa = 4.5
⇒ pOH = 9.5
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Most Upvoted Answer
The pKaof a weak acid (HA) is 4.5. The pOH of an aqueous buffered solu...
Given: pKa of weak acid (HA) = 4.5.

To find: pOH of aqueous buffered solution of HA in which 50% of the acid is ionized.

Step-by-step solution:

1. Calculate the pH of the solution.

pH = pKa + log ([A-]/[HA])

Where [A-] is the concentration of the conjugate base of the acid, and [HA] is the concentration of the weak acid.

Since 50% of the acid is ionized, the concentration of the conjugate base is equal to the concentration of the weak acid.

So, [A-] = [HA] = 0.5 M (assuming initial concentration of HA is 1 M).

pH = 4.5 + log (0.5/0.5) = 4.5

2. Calculate the pOH of the solution.

pH + pOH = 14

pOH = 14 - pH = 14 - 4.5 = 9.5

Therefore, the pOH of the aqueous buffered solution of HA in which 50% of the acid is ionized is 9.5.
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