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The precipitate of CaF2 (Ksp = 1.7 × 10-10) is obtained when equal volumes of the following are mixed
- a)10-4 M Ca3+ + 10-4 M F-
- b)10-2 M Ca2+ + 10-3 M F-
- c)10-5 M Ca2+ + 10-3 M F-
- d)10-3 M Ca2+ + 10-5 M F-
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The precipitate of CaF2(Ksp= 1.7 × 10-10) is obtained when equal ...
For ppt Qsp > Ksp
CaF2→ Ca2++2F–
Qsp = (Ca2+) (F–)2
(A) Qsp = 12.5 × 10–14
(B) Qsp = 12.5 × 10–10
(C) Qsp = 12.5 × 10–13
(D) Qsp = 12.5 × 10–15
Only (B) option will get precipitate.
CaF2→ Ca2++2F–
Qsp = (Ca2+) (F–)2
(A) Qsp = 12.5 × 10–14
(B) Qsp = 12.5 × 10–10
(C) Qsp = 12.5 × 10–13
(D) Qsp = 12.5 × 10–15
Only (B) option will get precipitate.
Most Upvoted Answer
The precipitate of CaF2(Ksp= 1.7 × 10-10) is obtained when equal ...
Explanation:
In order to determine the precipitate formed, we need to calculate the ion product (IP) for each option and compare it to the solubility product (Ksp) of CaF2. The ion product is calculated by multiplying the concentrations of the ions involved in the precipitation reaction.
a) 10^-4M Ca2+ and 10^-4M F-
IP = [Ca2+][F-] = (10^-4)(10^-4) = 10^-8
Since the ion product (10^-8) is less than the solubility product (1.7 x 10^-10), no precipitate of CaF2 will form.
b) 10^-2M Ca2+ and 10^-3M F-
IP = [Ca2+][F-] = (10^-2)(10^-3) = 10^-5
Since the ion product (10^-5) is greater than the solubility product (1.7 x 10^-10), a precipitate of CaF2 will form.
c) 10^-5M Ca2+ and 10^-3M F-
IP = [Ca2+][F-] = (10^-5)(10^-3) = 10^-8
Since the ion product (10^-8) is less than the solubility product (1.7 x 10^-10), no precipitate of CaF2 will form.
d) 10^-3M Ca2+ and 10^-5M F-
IP = [Ca2+][F-] = (10^-3)(10^-5) = 10^-8
Since the ion product (10^-8) is less than the solubility product (1.7 x 10^-10), no precipitate of CaF2 will form.
Therefore, the correct answer is option 'B' (10^-2M Ca2+ and 10^-3M F-), as the ion product (10^-5) is greater than the solubility product (1.7 x 10^-10), indicating that a precipitate of CaF2 will form when these concentrations are mixed.
In order to determine the precipitate formed, we need to calculate the ion product (IP) for each option and compare it to the solubility product (Ksp) of CaF2. The ion product is calculated by multiplying the concentrations of the ions involved in the precipitation reaction.
a) 10^-4M Ca2+ and 10^-4M F-
IP = [Ca2+][F-] = (10^-4)(10^-4) = 10^-8
Since the ion product (10^-8) is less than the solubility product (1.7 x 10^-10), no precipitate of CaF2 will form.
b) 10^-2M Ca2+ and 10^-3M F-
IP = [Ca2+][F-] = (10^-2)(10^-3) = 10^-5
Since the ion product (10^-5) is greater than the solubility product (1.7 x 10^-10), a precipitate of CaF2 will form.
c) 10^-5M Ca2+ and 10^-3M F-
IP = [Ca2+][F-] = (10^-5)(10^-3) = 10^-8
Since the ion product (10^-8) is less than the solubility product (1.7 x 10^-10), no precipitate of CaF2 will form.
d) 10^-3M Ca2+ and 10^-5M F-
IP = [Ca2+][F-] = (10^-3)(10^-5) = 10^-8
Since the ion product (10^-8) is less than the solubility product (1.7 x 10^-10), no precipitate of CaF2 will form.
Therefore, the correct answer is option 'B' (10^-2M Ca2+ and 10^-3M F-), as the ion product (10^-5) is greater than the solubility product (1.7 x 10^-10), indicating that a precipitate of CaF2 will form when these concentrations are mixed.
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The precipitate of CaF2(Ksp= 1.7 × 10-10) is obtained when equal volumes of the following are mixeda)10-4M Ca3++ 10-4M F-b)10-2M Ca2++ 10-3M F-c)10-5M Ca2++ 10-3M F-d)10-3M Ca2++ 10-5M F-Correct answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The precipitate of CaF2(Ksp= 1.7 × 10-10) is obtained when equal volumes of the following are mixeda)10-4M Ca3++ 10-4M F-b)10-2M Ca2++ 10-3M F-c)10-5M Ca2++ 10-3M F-d)10-3M Ca2++ 10-5M F-Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The precipitate of CaF2(Ksp= 1.7 × 10-10) is obtained when equal volumes of the following are mixeda)10-4M Ca3++ 10-4M F-b)10-2M Ca2++ 10-3M F-c)10-5M Ca2++ 10-3M F-d)10-3M Ca2++ 10-5M F-Correct answer is option 'B'. Can you explain this answer?.
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