Class 11 Exam > Class 11 Questions > pH of saturated solution of silver salt of mo...
Start Learning for Free
pH of saturated solution of silver salt of monobasic acid HA is found to be 9.
Find the Ksp of sparingly soluble salt Ag A(s).
Given : Ka(HA) = 10-10
- a)1.1 × 10-11
- b)1.1 × 10-10
- c)10-12
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
pH of saturated solution of silver salt of monobasic acid HA is found ...
Ksp = S (S–X) = 11 × 10–6 × 10–6
= 1.1 × 10–11
Most Upvoted Answer
pH of saturated solution of silver salt of monobasic acid HA is found ...
PH of a solution is a measure of its acidity or alkalinity. It is defined as the negative logarithm (base 10) of the concentration of hydrogen ions (H+) in the solution.
Given that the pH of the saturated solution of the silver salt AgA is 9, we can determine the concentration of H+ ions in the solution.
To find the concentration of H+ ions, we can use the formula:
pH = -log[H+]
9 = -log[H+]
Taking the antilog of both sides of the equation, we get:
[H+] = 10^(-9)
Now, we can relate the concentration of H+ ions to the dissociation of the monobasic acid HA. The dissociation of the acid can be represented by the following equation:
HA ⇌ H+ + A-
The dissociation constant (Ka) for the acid HA is given as 10^(-10).
Using the expression for Ka, we can write:
[H+][A-]/[HA] = 10^(-10)
Since the solution is saturated with the silver salt AgA, the concentration of A- ions is equal to the concentration of AgA. Therefore, we can substitute [A-] with [AgA] in the equation:
[H+][AgA]/[HA] = 10^(-10)
Since AgA is sparingly soluble, we can assume that its concentration is very small compared to the concentration of HA. Therefore, we can neglect the concentration of [AgA] in the denominator of the equation.
[H+]/[HA] ≈ 10^(-10)
Given that the pH of the solution is 9, we can substitute the concentration of H+ ions ([H+]) with 10^(-9) in the equation:
10^(-9)/[HA] ≈ 10^(-10)
Simplifying the equation, we get:
[HA] ≈ 10^(-9)
Therefore, the concentration of the monobasic acid HA is approximately 10^(-9) M.
Lastly, we can calculate the solubility product (Ksp) of the sparingly soluble salt AgA using the formula:
Ksp = [Ag+][A-]
Since the concentration of A- ions is equal to the concentration of AgA, we can substitute [A-] with [AgA] in the equation:
Ksp = [Ag+][AgA]
Given that the concentration of AgA is approximately 10^(-9) M, we can substitute this value in the equation:
Ksp = [Ag+](10^(-9))
Since the concentration of Ag+ ions is not given, we cannot determine the exact value of Ksp. However, we can conclude that the Ksp value will be on the order of 10^(-9).
Therefore, the correct answer is option A) 1.1 x 10^(-11).
Given that the pH of the saturated solution of the silver salt AgA is 9, we can determine the concentration of H+ ions in the solution.
To find the concentration of H+ ions, we can use the formula:
pH = -log[H+]
9 = -log[H+]
Taking the antilog of both sides of the equation, we get:
[H+] = 10^(-9)
Now, we can relate the concentration of H+ ions to the dissociation of the monobasic acid HA. The dissociation of the acid can be represented by the following equation:
HA ⇌ H+ + A-
The dissociation constant (Ka) for the acid HA is given as 10^(-10).
Using the expression for Ka, we can write:
[H+][A-]/[HA] = 10^(-10)
Since the solution is saturated with the silver salt AgA, the concentration of A- ions is equal to the concentration of AgA. Therefore, we can substitute [A-] with [AgA] in the equation:
[H+][AgA]/[HA] = 10^(-10)
Since AgA is sparingly soluble, we can assume that its concentration is very small compared to the concentration of HA. Therefore, we can neglect the concentration of [AgA] in the denominator of the equation.
[H+]/[HA] ≈ 10^(-10)
Given that the pH of the solution is 9, we can substitute the concentration of H+ ions ([H+]) with 10^(-9) in the equation:
10^(-9)/[HA] ≈ 10^(-10)
Simplifying the equation, we get:
[HA] ≈ 10^(-9)
Therefore, the concentration of the monobasic acid HA is approximately 10^(-9) M.
Lastly, we can calculate the solubility product (Ksp) of the sparingly soluble salt AgA using the formula:
Ksp = [Ag+][A-]
Since the concentration of A- ions is equal to the concentration of AgA, we can substitute [A-] with [AgA] in the equation:
Ksp = [Ag+][AgA]
Given that the concentration of AgA is approximately 10^(-9) M, we can substitute this value in the equation:
Ksp = [Ag+](10^(-9))
Since the concentration of Ag+ ions is not given, we cannot determine the exact value of Ksp. However, we can conclude that the Ksp value will be on the order of 10^(-9).
Therefore, the correct answer is option A) 1.1 x 10^(-11).
Free Test
FREE
| Start Free Test |
Community Answer
pH of saturated solution of silver salt of monobasic acid HA is found ...
D
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
Question Description
pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer?.
pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer?.
Solutions for pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice pH of saturated solution of silver salt of monobasic acid HA is found to be 9.Find the Kspof sparingly soluble salt Ag A(s).Given : Ka(HA) = 10-10a)1.1 × 10-11b)1.1 × 10-10c)10-12d)None of theseCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup