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What is the equilibrium expression for the reaction P4(S) + 5O2(g) 
P4O10(s) ?
P4O10(s) ? [AIEEE-2004]
- a)KC = [P4O10] / [P4] [O2]5
- b)KC = [P4O10] / 5 [P4] [O2]
- c)KC = [O2]5
- d)KC = 1/ [O2]5
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4...
In the expression for equilibrium constant (Kp or Kc) species state are not written (i.e., their molar concentrations are not taken as 1)
P4 (s) + 5O2 (g) ⇌ P4O10 (s)
Thus, Kc = 1/[O2]5
P4 (s) + 5O2 (g) ⇌ P4O10 (s)
Thus, Kc = 1/[O2]5
Most Upvoted Answer
What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4...
Equilibrium Expression:
The equilibrium expression for a chemical reaction is derived from the balanced chemical equation and represents the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium.
Explanation:
The given reaction is:
P4(S) + 5O2(g) -> P4O10(s)
To write the equilibrium expression, we consider the concentrations of the products (P4O10) and reactants (P4 and O2) at equilibrium.
The equilibrium expression is given by:
KC = [P4O10] / ([P4] * [O2]^5)
Reasoning:
The equilibrium expression is derived from the balanced chemical equation by using the stoichiometric coefficients as exponents on the concentrations of the reactants and products.
In this case, the stoichiometric coefficient of P4O10 is 1, so its concentration is simply represented as [P4O10].
The stoichiometric coefficient of P4 is also 1, so its concentration is represented as [P4].
The stoichiometric coefficient of O2 is 5, so its concentration is represented as [O2]^5.
The equilibrium expression represents the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. In this case, the equilibrium expression represents the ratio of the concentration of P4O10 to the concentrations of P4 and O2 raised to the power of 5.
The correct equilibrium expression for the given reaction is:
KC = [P4O10] / ([P4] * [O2]^5)
Correct Answer:
The correct answer is option 'D' (KC = 1/ [O2]^5).
The equilibrium expression for a chemical reaction is derived from the balanced chemical equation and represents the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium.
Explanation:
The given reaction is:
P4(S) + 5O2(g) -> P4O10(s)
To write the equilibrium expression, we consider the concentrations of the products (P4O10) and reactants (P4 and O2) at equilibrium.
The equilibrium expression is given by:
KC = [P4O10] / ([P4] * [O2]^5)
Reasoning:
The equilibrium expression is derived from the balanced chemical equation by using the stoichiometric coefficients as exponents on the concentrations of the reactants and products.
In this case, the stoichiometric coefficient of P4O10 is 1, so its concentration is simply represented as [P4O10].
The stoichiometric coefficient of P4 is also 1, so its concentration is represented as [P4].
The stoichiometric coefficient of O2 is 5, so its concentration is represented as [O2]^5.
The equilibrium expression represents the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. In this case, the equilibrium expression represents the ratio of the concentration of P4O10 to the concentrations of P4 and O2 raised to the power of 5.
The correct equilibrium expression for the given reaction is:
KC = [P4O10] / ([P4] * [O2]^5)
Correct Answer:
The correct answer is option 'D' (KC = 1/ [O2]^5).
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Community Answer
What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4...
Whenever u write a expression for Kc... you can't consider the compounds which are not in Gaseous state i.e. you can only write the compounds which are in Gaseous state while writing a equation for Kc
hence in the Kc equation... u can't consider [P4010] /[P4)
and I am pretty sure u know le Charlier's principle... so answer is option D
hence in the Kc equation... u can't consider [P4010] /[P4)
and I am pretty sure u know le Charlier's principle... so answer is option D
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What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer?.
What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer?.
Solutions for What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer?, a detailed solution for What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of What is the equilibrium expression for the reaction P4(S) + 5O2(g) P4O10(s) ?[AIEEE-2004]a)KC = [P4O10] / [P4] [O2]5b)KC = [P4O10] / 5 [P4] [O2]c)KC = [O2]5d)KC = 1/ [O2]5Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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