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NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions as
- a)M,M
- b)M,M/2
- c)M/2, M/5
- d)M/5, M/2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in a...
Thus, equivalent weight when reacted with NaOH = M
Most Upvoted Answer
NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in a...
Explanation:
Neutralisation reaction:
NaHC2O4 + NaOH → Na2C2O4 + 2H2O
Here, NaHC2O4 reacts with NaOH to give Na2C2O4 and 2 molecules of water.
The equivalent weight of NaHC2O4 is given by the formula:
Equivalent weight = Molecular weight / Basicity
where Basicity is the number of moles of NaOH required to neutralize one mole of NaHC2O4.
In this reaction, Basicity of NaHC2O4 is 2 (as 2 moles of NaOH is required to neutralize one mole of NaHC2O4).
Oxidation reaction:
5NaHC2O4 + 2KMnO4 + 8H2SO4 → 5Na2SO4 + K2SO4 + 2MnSO4 + 10CO2 + 8H2O
Here, NaHC2O4 reacts with KMnO4 in acidic medium to give products like Na2SO4, K2SO4, MnSO4, CO2, and water.
The equivalent weight of NaHC2O4 in this reaction is given by the formula:
Equivalent weight = Molecular weight / Change in Oxidation State
In this reaction, the oxidation state of carbon in NaHC2O4 changes from +3 to +4.
So, the change in oxidation state is 1.
Therefore, the equivalent weight of NaHC2O4 in this reaction is given by:
Equivalent weight = Molecular weight / 1 = Molecular weight
Thus, the relation between equivalent weight and molecular weight of NaHC2O4 in the given reactions is:
Equivalent weight in neutralization reaction = Molecular weight / 2
Equivalent weight in oxidation reaction = Molecular weight
Hence, the correct option is B.
Neutralisation reaction:
NaHC2O4 + NaOH → Na2C2O4 + 2H2O
Here, NaHC2O4 reacts with NaOH to give Na2C2O4 and 2 molecules of water.
The equivalent weight of NaHC2O4 is given by the formula:
Equivalent weight = Molecular weight / Basicity
where Basicity is the number of moles of NaOH required to neutralize one mole of NaHC2O4.
In this reaction, Basicity of NaHC2O4 is 2 (as 2 moles of NaOH is required to neutralize one mole of NaHC2O4).
Oxidation reaction:
5NaHC2O4 + 2KMnO4 + 8H2SO4 → 5Na2SO4 + K2SO4 + 2MnSO4 + 10CO2 + 8H2O
Here, NaHC2O4 reacts with KMnO4 in acidic medium to give products like Na2SO4, K2SO4, MnSO4, CO2, and water.
The equivalent weight of NaHC2O4 in this reaction is given by the formula:
Equivalent weight = Molecular weight / Change in Oxidation State
In this reaction, the oxidation state of carbon in NaHC2O4 changes from +3 to +4.
So, the change in oxidation state is 1.
Therefore, the equivalent weight of NaHC2O4 in this reaction is given by:
Equivalent weight = Molecular weight / 1 = Molecular weight
Thus, the relation between equivalent weight and molecular weight of NaHC2O4 in the given reactions is:
Equivalent weight in neutralization reaction = Molecular weight / 2
Equivalent weight in oxidation reaction = Molecular weight
Hence, the correct option is B.
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NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in a...
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NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer?.
NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer?.
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NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions asa)M,Mb)M,M/2c)M/2, M/5d)M/5, M/2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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