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The decomposition of hydrogen peroxide to form water and oxygen is an example of
- a)displacement reactions
- b)decomposition reactions
- c)disproportionation reaction
- d)combination reactions
Correct answer is option 'C'. Can you explain this answer?
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The decomposition of hydrogen peroxide to form water and oxygen is an ...
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The decomposition of hydrogen peroxide to form water and oxygen is an ...
Explanation:
Disproportionation reaction is a type of redox reaction in which a single substance is both oxidized and reduced, resulting in the formation of two different products. The decomposition of hydrogen peroxide is a classic example of disproportionation reaction.
The balanced chemical equation for the decomposition of hydrogen peroxide is as follows:
2H2O2 → 2H2O + O2
In this reaction, hydrogen peroxide (H2O2) is both oxidized and reduced. One of the oxygen atoms in H2O2 is oxidized to form oxygen gas (O2), while the other oxygen atom is reduced to form water (H2O). Hence, the same compound (H2O2) is giving rise to two different products (H2O and O2) through oxidation and reduction.
Therefore, the decomposition of hydrogen peroxide to form water and oxygen is an example of a disproportionation reaction.
Disproportionation reaction is a type of redox reaction in which a single substance is both oxidized and reduced, resulting in the formation of two different products. The decomposition of hydrogen peroxide is a classic example of disproportionation reaction.
The balanced chemical equation for the decomposition of hydrogen peroxide is as follows:
2H2O2 → 2H2O + O2
In this reaction, hydrogen peroxide (H2O2) is both oxidized and reduced. One of the oxygen atoms in H2O2 is oxidized to form oxygen gas (O2), while the other oxygen atom is reduced to form water (H2O). Hence, the same compound (H2O2) is giving rise to two different products (H2O and O2) through oxidation and reduction.
Therefore, the decomposition of hydrogen peroxide to form water and oxygen is an example of a disproportionation reaction.
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