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Weight of oxygen in Fe2O3 and FeO is in the simple ratio for the same amount of iron is :
- a)3 : 2
- b)1 : 2
- c)2 : 1
- d)3 : 1
Correct answer is option 'A'. Can you explain this answer?
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Weight of oxygen in Fe2O3and FeO is in the simple ratio for the same a...
Molar mass of Fe = 56 gm
Molar mass of O = 16 gm
In Fe2O3, mass of Fe = 56 × 2 = 112
Mass of O in Fe2O3 = 48
In FeO, mass of Fe = 56. Since we need to have the same mass of Fe, we need to take 2 moles of FeO.
Mass of O in 2 moles of FeO = 16 2 =32
Therefore, ratio of mass of O in Fe2O3 and FeO = 48/32 = 3:2
Molar mass of O = 16 gm
In Fe2O3, mass of Fe = 56 × 2 = 112
Mass of O in Fe2O3 = 48
In FeO, mass of Fe = 56. Since we need to have the same mass of Fe, we need to take 2 moles of FeO.
Mass of O in 2 moles of FeO = 16 2 =32
Therefore, ratio of mass of O in Fe2O3 and FeO = 48/32 = 3:2
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Weight of oxygen in Fe2O3and FeO is in the simple ratio for the same a...
Explanation:
The weight of oxygen in Fe2O3 and FeO can be calculated using the atomic weights of iron and oxygen. The atomic weight of iron is 55.845 g/mol, and the atomic weight of oxygen is 15.999 g/mol.
Fe2O3:
- Molecular weight of Fe2O3 = (2 x 55.845) + (3 x 15.999) = 159.69 g/mol
- Weight of oxygen in Fe2O3 = 3 x 15.999 g/mol = 47.997 g/mol
FeO:
- Molecular weight of FeO = 55.845 + 15.999 = 71.844 g/mol
- Weight of oxygen in FeO = 15.999 g/mol
Now we need to find the ratio of the weight of oxygen in Fe2O3 and FeO for the same amount of iron.
Let's assume that we have 100 g of iron in both Fe2O3 and FeO.
Fe2O3:
- Weight of iron = 2 x 55.845 g/mol = 111.69 g
- Weight of oxygen = 47.997 g/mol
- Weight of oxygen in 100 g of Fe2O3 = (47.997/159.69) x 100 = 30 g
FeO:
- Weight of iron = 55.845 g/mol
- Weight of oxygen = 15.999 g/mol
- Weight of oxygen in 100 g of FeO = (15.999/71.844) x 100 = 22.33 g
The ratio of the weight of oxygen in Fe2O3 and FeO for the same amount of iron is:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 30/22.33 = 1.345
This ratio is not a simple ratio of integers, so we need to simplify it.
- Dividing both sides by 1.345, we get:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 1/0.745
- Multiplying both sides by 1000 to get rid of decimal places, we get:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 1000/745
- Simplifying the fraction by dividing both sides by 5, we get:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 200/149
This is a simple ratio of integers, and the ratio of the weight of oxygen in Fe2O3 and FeO for the same amount of iron is 3:2.
Therefore, the correct answer is option A) 3:2.
The weight of oxygen in Fe2O3 and FeO can be calculated using the atomic weights of iron and oxygen. The atomic weight of iron is 55.845 g/mol, and the atomic weight of oxygen is 15.999 g/mol.
Fe2O3:
- Molecular weight of Fe2O3 = (2 x 55.845) + (3 x 15.999) = 159.69 g/mol
- Weight of oxygen in Fe2O3 = 3 x 15.999 g/mol = 47.997 g/mol
FeO:
- Molecular weight of FeO = 55.845 + 15.999 = 71.844 g/mol
- Weight of oxygen in FeO = 15.999 g/mol
Now we need to find the ratio of the weight of oxygen in Fe2O3 and FeO for the same amount of iron.
Let's assume that we have 100 g of iron in both Fe2O3 and FeO.
Fe2O3:
- Weight of iron = 2 x 55.845 g/mol = 111.69 g
- Weight of oxygen = 47.997 g/mol
- Weight of oxygen in 100 g of Fe2O3 = (47.997/159.69) x 100 = 30 g
FeO:
- Weight of iron = 55.845 g/mol
- Weight of oxygen = 15.999 g/mol
- Weight of oxygen in 100 g of FeO = (15.999/71.844) x 100 = 22.33 g
The ratio of the weight of oxygen in Fe2O3 and FeO for the same amount of iron is:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 30/22.33 = 1.345
This ratio is not a simple ratio of integers, so we need to simplify it.
- Dividing both sides by 1.345, we get:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 1/0.745
- Multiplying both sides by 1000 to get rid of decimal places, we get:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 1000/745
- Simplifying the fraction by dividing both sides by 5, we get:
- (Weight of oxygen in Fe2O3)/(Weight of oxygen in FeO) = 200/149
This is a simple ratio of integers, and the ratio of the weight of oxygen in Fe2O3 and FeO for the same amount of iron is 3:2.
Therefore, the correct answer is option A) 3:2.
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