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If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then the correct option is
  • a)
    The resulting solution contains 18 gm of water and 118 gm H2SO4
  • b)
    The resulting solution contains 9 gm of water and 59 gm H2SO4
  • c)
    The resulting solution contains only 118 gm pure H2SO4
  • d)
    The resulting solution contains 68 gm of pure H2SO4
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then th...
118 % ⇒ 100 g sample uses 18 g water
⇒ 50 g sample need 9 g water
(50 g + 18 g water)
⇒ 59 g H2SO4 + 9 g water
View all questions of this test
Most Upvoted Answer
If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then th...
The given question is:
If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then the correct option is:

a) The resulting solution contains 18 gm of water and 118 gm H2SO4
b) The resulting solution contains 9 gm of water and 59 gm H2SO4
c) The resulting solution contains only 118 gm pure H2SO4
d) The resulting solution contains 68 gm of pure H2SO4

Explanation:
Step 1: Calculate the amount of H2SO4 in the oleum sample
Given that the oleum sample is rated as 118%, which means it contains 118% of the H2SO4 it would contain if it were pure.
Let's assume the amount of pure H2SO4 in the oleum sample is x grams.
So, 118% of x is equal to 50 grams.
Therefore, (118/100) * x = 50
Simplifying the equation, we get x = (50 * 100) / 118
x ≈ 42.37 grams

Step 2: Calculate the total amount of solution after mixing
The total amount of solution after mixing is the sum of the weights of the oleum sample and water.
Total weight = 50 grams (oleum sample) + 18 grams (water)
Total weight ≈ 68 grams

Step 3: Calculate the amount of H2SO4 in the resulting solution
Since the oleum sample contains 42.37 grams of pure H2SO4, and we are mixing it with 18 grams of water, the total amount of H2SO4 in the resulting solution will be:
42.37 grams (H2SO4 in oleum sample) + 0 grams (H2SO4 in water) = 42.37 grams

Step 4: Calculate the amount of water in the resulting solution
The resulting solution contains 18 grams of water, as given in the question.

Conclusion:
Therefore, the correct option is b) The resulting solution contains 9 gm of water and 59 gm H2SO4.
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If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then the correct option isa)The resulting solution contains 18 gm of water and 118 gm H2SO4b)The resulting solution contains 9 gm of water and 59 gm H2SO4c)The resulting solution contains only 118 gm pure H2SO4d)The resulting solution contains 68 gm of pure H2SO4Correct answer is option 'B'. Can you explain this answer?
Question Description
If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then the correct option isa)The resulting solution contains 18 gm of water and 118 gm H2SO4b)The resulting solution contains 9 gm of water and 59 gm H2SO4c)The resulting solution contains only 118 gm pure H2SO4d)The resulting solution contains 68 gm of pure H2SO4Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then the correct option isa)The resulting solution contains 18 gm of water and 118 gm H2SO4b)The resulting solution contains 9 gm of water and 59 gm H2SO4c)The resulting solution contains only 118 gm pure H2SO4d)The resulting solution contains 68 gm of pure H2SO4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 50 gm oleum sample rated as 118% is mixed with 18 gm water, then the correct option isa)The resulting solution contains 18 gm of water and 118 gm H2SO4b)The resulting solution contains 9 gm of water and 59 gm H2SO4c)The resulting solution contains only 118 gm pure H2SO4d)The resulting solution contains 68 gm of pure H2SO4Correct answer is option 'B'. Can you explain this answer?.
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