Which among the following does not exhibit geometric isomerisma)1-hexe...
Alkenes like 1-hexene when flipped from top to bottom they have identical structures and also they have C=CH2 unit which does not exist as cis- trans isomers.
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Which among the following does not exhibit geometric isomerisma)1-hexe...
Explanation:
Geometric isomerism is a type of stereoisomerism in which the isomers differ in their spatial arrangement around a double bond or a ring. It occurs when there is restricted rotation around a bond due to the presence of bulky groups or a double bond.
To determine whether a compound exhibits geometric isomerism, we need to examine the arrangement of substituents around the double bond. If there are two different groups on each carbon of the double bond, and these groups are arranged differently, then geometric isomerism is possible.
Let's analyze each option to see if it exhibits geometric isomerism:
1-hexene:
In 1-hexene, there is a double bond between the first and second carbon atoms. The two substituents on each carbon are a hydrogen atom and a methyl group. Since both carbons have the same substituents, there is no difference in their spatial arrangement, and thus 1-hexene does not exhibit geometric isomerism.
2-hexene:
In 2-hexene, there is a double bond between the second and third carbon atoms. The two substituents on each carbon are a hydrogen atom and a methyl group. Since both carbons have the same substituents, there is no difference in their spatial arrangement, and thus 2-hexene does not exhibit geometric isomerism.
3-hexene:
In 3-hexene, there is a double bond between the third and fourth carbon atoms. The two substituents on each carbon are a hydrogen atom and a methyl group. Since both carbons have the same substituents, there is no difference in their spatial arrangement, and thus 3-hexene does not exhibit geometric isomerism.
4-hexene:
In 4-hexene, there is a double bond between the fourth and fifth carbon atoms. The two substituents on each carbon are a hydrogen atom and a methyl group. Since both carbons have the same substituents, there is no difference in their spatial arrangement, and thus 4-hexene does not exhibit geometric isomerism.
Therefore, out of the given options, option A (1-hexene) does not exhibit geometric isomerism.
Which among the following does not exhibit geometric isomerisma)1-hexe...
- Double Bond Location: Between C1 and C2.
- Substituents:
- C1: Attached to two hydrogen atoms (H and H) and the C2 carbon.
- C2: Attached to a hydrogen atom (H) and the C3 carbon.
- Analysis:
- C1 has two identical substituents (both hydrogens).
- Since one of the carbons in the double bond (C1) does not have two different substituents, geometric isomerism is not possible.
- Conclusion: Does not exhibit geometric isomerism.