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Calculate the number of Zr-B bond in Zr(BH4)4:
    Correct answer is '0'. Can you explain this answer?
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    Calculate the number of Zr-B bond in Zr(BH4)4:Correct answer is '0'. C...
    Explanation:

    Zr(BH4)4 is an ionic compound consisting of Zr4+ cation and BH4- anion. The BH4- anion is tetrahedral in shape and each boron atom is bonded to four hydrogen atoms. There is no covalent bond between boron and zirconium atoms.

    Calculation:

    Zr(BH4)4 contains one Zr4+ cation and four BH4- anions. The charge on the Zr4+ cation is +4 and the charge on each BH4- anion is -1. Therefore, the total charge of the compound is:

    Charge of Zr4+ cation = +4
    Charge of 4 BH4- anions = -4
    Total charge = 0

    Since the compound has a total charge of 0, it means that the number of positive charges (Zr4+ cations) is equal to the number of negative charges (BH4- anions). Therefore, there are no Zr-B bonds in Zr(BH4)4.

    Conclusion:

    The number of Zr-B bonds in Zr(BH4)4 is 0, as there are no covalent bonds between boron and zirconium atoms in the compound.
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