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Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
Q. If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?
Correct answer is '2'. Can you explain this answer?
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Direction (Q. No. 17 - 20) This section contains 4 questions. When wor...
Explanation:
When a pure enantiomer of 5-bromo-2-hexene is treated with Br2 CCl4, two different tribromides would be formed.
Reasoning:
1. The reaction of a pure enantiomer of 5-bromo-2-hexene with Br2 CCl4 results in the addition of bromine atoms to the double bond, forming a tribromide.
2. Since the starting compound is a pure enantiomer, it means that only one enantiomer is present.
3. When bromine atoms are added to the double bond, two different tribromides are formed due to the presence of a chiral center.
4. The chiral center is formed by the replacement of one of the hydrogen atoms attached to the carbon atom adjacent to the double bond with a bromine atom.
5. This results in two different possible arrangements of bromine atoms around the chiral center, giving rise to two different enantiomers of the tribromide.
Therefore, when a pure enantiomer of 5-bromo-2-hexene is treated with Br2 CCl4, two different tribromides would be formed.
When a pure enantiomer of 5-bromo-2-hexene is treated with Br2 CCl4, two different tribromides would be formed.
Reasoning:
1. The reaction of a pure enantiomer of 5-bromo-2-hexene with Br2 CCl4 results in the addition of bromine atoms to the double bond, forming a tribromide.
2. Since the starting compound is a pure enantiomer, it means that only one enantiomer is present.
3. When bromine atoms are added to the double bond, two different tribromides are formed due to the presence of a chiral center.
4. The chiral center is formed by the replacement of one of the hydrogen atoms attached to the carbon atom adjacent to the double bond with a bromine atom.
5. This results in two different possible arrangements of bromine atoms around the chiral center, giving rise to two different enantiomers of the tribromide.
Therefore, when a pure enantiomer of 5-bromo-2-hexene is treated with Br2 CCl4, two different tribromides would be formed.
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Direction (Q. No. 17 - 20) This section contains 4 questions. When wor...
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Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer?
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Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer?.
Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer?.
Solutions for Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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