Class 11 Exam  >  Class 11 Questions  >  Direction (Q. No. 17 - 20) This section conta... Start Learning for Free
Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
Q. If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?
    Correct answer is '2'. Can you explain this answer?
    Most Upvoted Answer
    Direction (Q. No. 17 - 20) This section contains 4 questions. When wor...
    Explanation:

    When a pure enantiomer of 5-bromo-2-hexene is treated with Br2 CCl4, two different tribromides would be formed.

    Reasoning:

    1. The reaction of a pure enantiomer of 5-bromo-2-hexene with Br2 CCl4 results in the addition of bromine atoms to the double bond, forming a tribromide.
    2. Since the starting compound is a pure enantiomer, it means that only one enantiomer is present.
    3. When bromine atoms are added to the double bond, two different tribromides are formed due to the presence of a chiral center.
    4. The chiral center is formed by the replacement of one of the hydrogen atoms attached to the carbon atom adjacent to the double bond with a bromine atom.
    5. This results in two different possible arrangements of bromine atoms around the chiral center, giving rise to two different enantiomers of the tribromide.

    Therefore, when a pure enantiomer of 5-bromo-2-hexene is treated with Br2 CCl4, two different tribromides would be formed.
    Free Test
    Community Answer
    Direction (Q. No. 17 - 20) This section contains 4 questions. When wor...
    No
    Attention Class 11 Students!
    To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
    Explore Courses for Class 11 exam

    Top Courses for Class 11

    Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer?
    Question Description
    Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer?.
    Solutions for Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
    Here you can find the meaning of Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer?, a detailed solution for Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? has been provided alongside types of Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?Correct answer is '2'. Can you explain this answer? tests, examples and also practice Class 11 tests.
    Explore Courses for Class 11 exam

    Top Courses for Class 11

    Explore Courses
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev