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Direction (Q. Nos. 17 - 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).
Q. If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?
Correct answer is '6'. Can you explain this answer?
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Direction (Q. Nos. 17- 20) This section contains 4 questions. When wor...
2 is the right answer.
Alcoholic KOH causes dehydrohalogenation reaction i.e. elimination reaction.
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Direction (Q. Nos. 17- 20) This section contains 4 questions. When wor...
Understanding 3-Bromo-4-Methyl Hexane
3-Bromo-4-methyl hexane is a six-carbon alkane with a bromine substituent at the third carbon and a methyl group at the fourth carbon. The molecular structure can undergo elimination reactions, typically via dehydrohalogenation when treated with ethanolic KOH.
Elimination Reaction
- The KOH acts as a strong base, facilitating the removal of the bromine atom and a hydrogen atom from adjacent carbon atoms.
- This process leads to the formation of alkenes through the elimination of HBr.
Possible Alkenes Formed
When 3-bromo-4-methyl hexane undergoes elimination, two distinct alkenes can be formed:
1. Alkene A (3-Methylhex-3-ene):
- Formation occurs by the elimination of H from the second carbon and Br from the third carbon.
- Structure: CH3-CH=CH-CH(CH3)-CH2-CH3
2. Alkene B (4-Methylhex-2-ene):
- Formation occurs by the elimination of H from the fourth carbon and Br from the third carbon.
- Structure: CH3-CH=CH-CH(CH3)-CH2-CH3
Conclusion
- The elimination of HBr can lead to two different alkenes due to the possibility of choosing different hydrogen atoms to eliminate along with the bromine atom.
- Hence, the reaction of 3-bromo-4-methyl hexane with ethanolic KOH results in two different alkenes.
This insight helps in understanding the concept of regioselectivity in elimination reactions in organic chemistry.
3-Bromo-4-methyl hexane is a six-carbon alkane with a bromine substituent at the third carbon and a methyl group at the fourth carbon. The molecular structure can undergo elimination reactions, typically via dehydrohalogenation when treated with ethanolic KOH.
Elimination Reaction
- The KOH acts as a strong base, facilitating the removal of the bromine atom and a hydrogen atom from adjacent carbon atoms.
- This process leads to the formation of alkenes through the elimination of HBr.
Possible Alkenes Formed
When 3-bromo-4-methyl hexane undergoes elimination, two distinct alkenes can be formed:
1. Alkene A (3-Methylhex-3-ene):
- Formation occurs by the elimination of H from the second carbon and Br from the third carbon.
- Structure: CH3-CH=CH-CH(CH3)-CH2-CH3
2. Alkene B (4-Methylhex-2-ene):
- Formation occurs by the elimination of H from the fourth carbon and Br from the third carbon.
- Structure: CH3-CH=CH-CH(CH3)-CH2-CH3
Conclusion
- The elimination of HBr can lead to two different alkenes due to the possibility of choosing different hydrogen atoms to eliminate along with the bromine atom.
- Hence, the reaction of 3-bromo-4-methyl hexane with ethanolic KOH results in two different alkenes.
This insight helps in understanding the concept of regioselectivity in elimination reactions in organic chemistry.
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Direction (Q. Nos. 17- 20) This section contains 4 questions. When wor...
2 is the right answer.
Alcoholic KOH causes dehydrohalogenation reaction i.e. elimination reaction.
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Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer?
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Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer?.
Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer?.
Solutions for Direction (Q. Nos. 17- 20) This section contains 4 questions. When worked o u t wili result in an integer from 0 to 9 (both inclusive).Q.If 3-bromo-4-methyl hexane is treated with ethanolic KOH solution, how many different alkenes would be formed?Correct answer is '6'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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