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Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared
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the Class 11 exam syllabus. Information about Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Passage IIAn organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI isa)A pair of enantiomers is formed in equal amountb)Two pairs of diastereomers are formec)Only a meso-dichloride is formedd)Only one pair of diastereomers is formedCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.